Metamath Proof Explorer


Theorem oppcmndc

Description: The opposite category of a category whose base set is a singleton or an empty set has the same base and hom-sets as the original category. (Contributed by Zhi Wang, 16-Oct-2025)

Ref Expression
Hypotheses oppcendc.o ⊢ 𝑂 = ( oppCat ‘ 𝐶 )
oppcendc.b ⊢ 𝐵 = ( Base ‘ 𝐶 )
oppcmndc.x ⊢ ( 𝜑 → 𝐵 = { 𝑋 } )
Assertion oppcmndc ( 𝜑 → ( Homf ‘ 𝐶 ) = ( Homf ‘ 𝑂 ) )

Proof

Step Hyp Ref Expression
1 oppcendc.o ⊢ 𝑂 = ( oppCat ‘ 𝐶 )
2 oppcendc.b ⊢ 𝐵 = ( Base ‘ 𝐶 )
3 oppcmndc.x ⊢ ( 𝜑 → 𝐵 = { 𝑋 } )
4 eqid ⊢ ( Hom ‘ 𝐶 ) = ( Hom ‘ 𝐶 )
5 3 oppcmndclem ⊢ ( ( 𝜑 ∧ ( 𝑥 ∈ 𝐵 ∧ 𝑦 ∈ 𝐵 ) ) → ( 𝑥 ≠ 𝑦 → ( 𝑥 ( Hom ‘ 𝐶 ) 𝑦 ) = ∅ ) )
6 1 2 4 5 oppcendc ⊢ ( 𝜑 → ( Homf ‘ 𝐶 ) = ( Homf ‘ 𝑂 ) )