Metamath Proof Explorer


Theorem prcofval

Description: Value of the pre-composition functor. (Contributed by Zhi Wang, 2-Nov-2025)

Ref Expression
Hypotheses prcofvalg.b ⊢ 𝐵 = ( 𝐷 Func 𝐸 )
prcofvalg.n ⊢ 𝑁 = ( 𝐷 Nat 𝐸 )
prcofvala.d ⊢ ( 𝜑 → 𝐷 ∈ 𝑉 )
prcofvala.e ⊢ ( 𝜑 → 𝐸 ∈ 𝑊 )
prcofval.r ⊢ Rel 𝑅
prcofval.f ⊢ ( 𝜑 → 𝐹 𝑅 𝐺 )
Assertion prcofval ( 𝜑 → ( ⟨ 𝐷 , 𝐸 ⟩ −∘F ⟨ 𝐹 , 𝐺 ⟩ ) = ⟨ ( 𝑘 ∈ 𝐵 ↦ ( 𝑘 ∘func ⟨ 𝐹 , 𝐺 ⟩ ) ) , ( 𝑘 ∈ 𝐵 , 𝑙 ∈ 𝐵 ↦ ( 𝑎 ∈ ( 𝑘 𝑁 𝑙 ) ↦ ( 𝑎 ∘ 𝐹 ) ) ) ⟩ )

Proof

Step Hyp Ref Expression
1 prcofvalg.b ⊢ 𝐵 = ( 𝐷 Func 𝐸 )
2 prcofvalg.n ⊢ 𝑁 = ( 𝐷 Nat 𝐸 )
3 prcofvala.d ⊢ ( 𝜑 → 𝐷 ∈ 𝑉 )
4 prcofvala.e ⊢ ( 𝜑 → 𝐸 ∈ 𝑊 )
5 prcofval.r ⊢ Rel 𝑅
6 prcofval.f ⊢ ( 𝜑 → 𝐹 𝑅 𝐺 )
7 opex ⊢ ⟨ 𝐹 , 𝐺 ⟩ ∈ V
8 7 a1i ⊢ ( 𝜑 → ⟨ 𝐹 , 𝐺 ⟩ ∈ V )
9 1 2 3 4 8 prcofvala ⊢ ( 𝜑 → ( ⟨ 𝐷 , 𝐸 ⟩ −∘F ⟨ 𝐹 , 𝐺 ⟩ ) = ⟨ ( 𝑘 ∈ 𝐵 ↦ ( 𝑘 ∘func ⟨ 𝐹 , 𝐺 ⟩ ) ) , ( 𝑘 ∈ 𝐵 , 𝑙 ∈ 𝐵 ↦ ( 𝑎 ∈ ( 𝑘 𝑁 𝑙 ) ↦ ( 𝑎 ∘ ( 1st ‘ ⟨ 𝐹 , 𝐺 ⟩ ) ) ) ) ⟩ )
10 5 brrelex12i ⊢ ( 𝐹 𝑅 𝐺 → ( 𝐹 ∈ V ∧ 𝐺 ∈ V ) )
11 op1stg ⊢ ( ( 𝐹 ∈ V ∧ 𝐺 ∈ V ) → ( 1st ‘ ⟨ 𝐹 , 𝐺 ⟩ ) = 𝐹 )
12 6 10 11 3syl ⊢ ( 𝜑 → ( 1st ‘ ⟨ 𝐹 , 𝐺 ⟩ ) = 𝐹 )
13 12 coeq2d ⊢ ( 𝜑 → ( 𝑎 ∘ ( 1st ‘ ⟨ 𝐹 , 𝐺 ⟩ ) ) = ( 𝑎 ∘ 𝐹 ) )
14 13 mpteq2dv ⊢ ( 𝜑 → ( 𝑎 ∈ ( 𝑘 𝑁 𝑙 ) ↦ ( 𝑎 ∘ ( 1st ‘ ⟨ 𝐹 , 𝐺 ⟩ ) ) ) = ( 𝑎 ∈ ( 𝑘 𝑁 𝑙 ) ↦ ( 𝑎 ∘ 𝐹 ) ) )
15 14 mpoeq3dv ⊢ ( 𝜑 → ( 𝑘 ∈ 𝐵 , 𝑙 ∈ 𝐵 ↦ ( 𝑎 ∈ ( 𝑘 𝑁 𝑙 ) ↦ ( 𝑎 ∘ ( 1st ‘ ⟨ 𝐹 , 𝐺 ⟩ ) ) ) ) = ( 𝑘 ∈ 𝐵 , 𝑙 ∈ 𝐵 ↦ ( 𝑎 ∈ ( 𝑘 𝑁 𝑙 ) ↦ ( 𝑎 ∘ 𝐹 ) ) ) )
16 15 opeq2d ⊢ ( 𝜑 → ⟨ ( 𝑘 ∈ 𝐵 ↦ ( 𝑘 ∘func ⟨ 𝐹 , 𝐺 ⟩ ) ) , ( 𝑘 ∈ 𝐵 , 𝑙 ∈ 𝐵 ↦ ( 𝑎 ∈ ( 𝑘 𝑁 𝑙 ) ↦ ( 𝑎 ∘ ( 1st ‘ ⟨ 𝐹 , 𝐺 ⟩ ) ) ) ) ⟩ = ⟨ ( 𝑘 ∈ 𝐵 ↦ ( 𝑘 ∘func ⟨ 𝐹 , 𝐺 ⟩ ) ) , ( 𝑘 ∈ 𝐵 , 𝑙 ∈ 𝐵 ↦ ( 𝑎 ∈ ( 𝑘 𝑁 𝑙 ) ↦ ( 𝑎 ∘ 𝐹 ) ) ) ⟩ )
17 9 16 eqtrd ⊢ ( 𝜑 → ( ⟨ 𝐷 , 𝐸 ⟩ −∘F ⟨ 𝐹 , 𝐺 ⟩ ) = ⟨ ( 𝑘 ∈ 𝐵 ↦ ( 𝑘 ∘func ⟨ 𝐹 , 𝐺 ⟩ ) ) , ( 𝑘 ∈ 𝐵 , 𝑙 ∈ 𝐵 ↦ ( 𝑎 ∈ ( 𝑘 𝑁 𝑙 ) ↦ ( 𝑎 ∘ 𝐹 ) ) ) ⟩ )