Metamath Proof Explorer


Theorem rabssrabd

Description: Subclass of a restricted class abstraction. (Contributed by AV, 4-Jun-2022)

Ref Expression
Hypotheses rabssrabd.1 ⊢ ( 𝜑 → 𝐴 ⊆ 𝐵 )
rabssrabd.2 ⊢ ( ( 𝜑 ∧ 𝜓 ∧ 𝑥 ∈ 𝐴 ) → 𝜒 )
Assertion rabssrabd ( 𝜑 → { 𝑥 ∈ 𝐴 ∣ 𝜓 } ⊆ { 𝑥 ∈ 𝐵 ∣ 𝜒 } )

Proof

Step Hyp Ref Expression
1 rabssrabd.1 ⊢ ( 𝜑 → 𝐴 ⊆ 𝐵 )
2 rabssrabd.2 ⊢ ( ( 𝜑 ∧ 𝜓 ∧ 𝑥 ∈ 𝐴 ) → 𝜒 )
3 3anan32 ⊢ ( ( 𝜑 ∧ 𝜓 ∧ 𝑥 ∈ 𝐴 ) ↔ ( ( 𝜑 ∧ 𝑥 ∈ 𝐴 ) ∧ 𝜓 ) )
4 3 2 sylbir ⊢ ( ( ( 𝜑 ∧ 𝑥 ∈ 𝐴 ) ∧ 𝜓 ) → 𝜒 )
5 4 ex ⊢ ( ( 𝜑 ∧ 𝑥 ∈ 𝐴 ) → ( 𝜓 → 𝜒 ) )
6 5 ss2rabdv ⊢ ( 𝜑 → { 𝑥 ∈ 𝐴 ∣ 𝜓 } ⊆ { 𝑥 ∈ 𝐴 ∣ 𝜒 } )
7 rabss2 ⊢ ( 𝐴 ⊆ 𝐵 → { 𝑥 ∈ 𝐴 ∣ 𝜒 } ⊆ { 𝑥 ∈ 𝐵 ∣ 𝜒 } )
8 1 7 syl ⊢ ( 𝜑 → { 𝑥 ∈ 𝐴 ∣ 𝜒 } ⊆ { 𝑥 ∈ 𝐵 ∣ 𝜒 } )
9 6 8 sstrd ⊢ ( 𝜑 → { 𝑥 ∈ 𝐴 ∣ 𝜓 } ⊆ { 𝑥 ∈ 𝐵 ∣ 𝜒 } )