Metamath Proof Explorer


Theorem reflexg

Description: Two ways of saying a relation is reflexive over its domain and range. (Contributed by RP, 4-Aug-2020)

Ref Expression
Assertion reflexg ( ( I ↾ ( dom 𝐴 ∪ ran 𝐴 ) ) ⊆ 𝐴 ↔ ∀ 𝑥𝑦 ( 𝑥 𝐴 𝑦 → ( 𝑥 𝐴 𝑥𝑦 𝐴 𝑦 ) ) )

Proof

Step Hyp Ref Expression
1 undmrnresiss ( ( I ↾ ( dom 𝐴 ∪ ran 𝐴 ) ) ⊆ 𝐴 ↔ ∀ 𝑥𝑦 ( 𝑥 𝐴 𝑦 → ( 𝑥 𝐴 𝑥𝑦 𝐴 𝑦 ) ) )