Step |
Hyp |
Ref |
Expression |
1 |
|
trclfvub |
⊢ ( 𝑅 ∈ 𝑉 → ( t+ ‘ 𝑅 ) ⊆ ( 𝑅 ∪ ( dom 𝑅 × ran 𝑅 ) ) ) |
2 |
|
rnss |
⊢ ( ( t+ ‘ 𝑅 ) ⊆ ( 𝑅 ∪ ( dom 𝑅 × ran 𝑅 ) ) → ran ( t+ ‘ 𝑅 ) ⊆ ran ( 𝑅 ∪ ( dom 𝑅 × ran 𝑅 ) ) ) |
3 |
1 2
|
syl |
⊢ ( 𝑅 ∈ 𝑉 → ran ( t+ ‘ 𝑅 ) ⊆ ran ( 𝑅 ∪ ( dom 𝑅 × ran 𝑅 ) ) ) |
4 |
|
rnun |
⊢ ran ( 𝑅 ∪ ( dom 𝑅 × ran 𝑅 ) ) = ( ran 𝑅 ∪ ran ( dom 𝑅 × ran 𝑅 ) ) |
5 |
4
|
a1i |
⊢ ( 𝑅 ∈ 𝑉 → ran ( 𝑅 ∪ ( dom 𝑅 × ran 𝑅 ) ) = ( ran 𝑅 ∪ ran ( dom 𝑅 × ran 𝑅 ) ) ) |
6 |
|
rnxpss |
⊢ ran ( dom 𝑅 × ran 𝑅 ) ⊆ ran 𝑅 |
7 |
|
ssequn2 |
⊢ ( ran ( dom 𝑅 × ran 𝑅 ) ⊆ ran 𝑅 ↔ ( ran 𝑅 ∪ ran ( dom 𝑅 × ran 𝑅 ) ) = ran 𝑅 ) |
8 |
6 7
|
mpbi |
⊢ ( ran 𝑅 ∪ ran ( dom 𝑅 × ran 𝑅 ) ) = ran 𝑅 |
9 |
5 8
|
eqtrdi |
⊢ ( 𝑅 ∈ 𝑉 → ran ( 𝑅 ∪ ( dom 𝑅 × ran 𝑅 ) ) = ran 𝑅 ) |
10 |
3 9
|
sseqtrd |
⊢ ( 𝑅 ∈ 𝑉 → ran ( t+ ‘ 𝑅 ) ⊆ ran 𝑅 ) |
11 |
|
trclfvlb |
⊢ ( 𝑅 ∈ 𝑉 → 𝑅 ⊆ ( t+ ‘ 𝑅 ) ) |
12 |
|
rnss |
⊢ ( 𝑅 ⊆ ( t+ ‘ 𝑅 ) → ran 𝑅 ⊆ ran ( t+ ‘ 𝑅 ) ) |
13 |
11 12
|
syl |
⊢ ( 𝑅 ∈ 𝑉 → ran 𝑅 ⊆ ran ( t+ ‘ 𝑅 ) ) |
14 |
10 13
|
eqssd |
⊢ ( 𝑅 ∈ 𝑉 → ran ( t+ ‘ 𝑅 ) = ran 𝑅 ) |