Metamath Proof Explorer


Theorem rspc2

Description: Restricted specialization with two quantifiers, using implicit substitution. (Contributed by NM, 9-Nov-2012)

Ref Expression
Hypotheses rspc2.1 ⊢ Ⅎ 𝑥 𝜒
rspc2.2 ⊢ Ⅎ 𝑦 𝜓
rspc2.3 ⊢ ( 𝑥 = 𝐴 → ( 𝜑 ↔ 𝜒 ) )
rspc2.4 ⊢ ( 𝑦 = 𝐵 → ( 𝜒 ↔ 𝜓 ) )
Assertion rspc2 ( ( 𝐴 ∈ 𝐶 ∧ 𝐵 ∈ 𝐷 ) → ( ∀ 𝑥 ∈ 𝐶 ∀ 𝑦 ∈ 𝐷 𝜑 → 𝜓 ) )

Proof

Step Hyp Ref Expression
1 rspc2.1 ⊢ Ⅎ 𝑥 𝜒
2 rspc2.2 ⊢ Ⅎ 𝑦 𝜓
3 rspc2.3 ⊢ ( 𝑥 = 𝐴 → ( 𝜑 ↔ 𝜒 ) )
4 rspc2.4 ⊢ ( 𝑦 = 𝐵 → ( 𝜒 ↔ 𝜓 ) )
5 nfcv ⊢ Ⅎ 𝑥 𝐷
6 5 1 nfralw ⊢ Ⅎ 𝑥 ∀ 𝑦 ∈ 𝐷 𝜒
7 3 ralbidv ⊢ ( 𝑥 = 𝐴 → ( ∀ 𝑦 ∈ 𝐷 𝜑 ↔ ∀ 𝑦 ∈ 𝐷 𝜒 ) )
8 6 7 rspc ⊢ ( 𝐴 ∈ 𝐶 → ( ∀ 𝑥 ∈ 𝐶 ∀ 𝑦 ∈ 𝐷 𝜑 → ∀ 𝑦 ∈ 𝐷 𝜒 ) )
9 2 4 rspc ⊢ ( 𝐵 ∈ 𝐷 → ( ∀ 𝑦 ∈ 𝐷 𝜒 → 𝜓 ) )
10 8 9 sylan9 ⊢ ( ( 𝐴 ∈ 𝐶 ∧ 𝐵 ∈ 𝐷 ) → ( ∀ 𝑥 ∈ 𝐶 ∀ 𝑦 ∈ 𝐷 𝜑 → 𝜓 ) )