Metamath Proof Explorer


Theorem scafeq

Description: If the scalar multiplication operation is already a function, the functionalization of it is equal to the original operation. (Contributed by Mario Carneiro, 5-Oct-2015)

Ref Expression
Hypotheses scaffval.b ⊢ 𝐵 = ( Base ‘ 𝑊 )
scaffval.f ⊢ 𝐹 = ( Scalar ‘ 𝑊 )
scaffval.k ⊢ 𝐾 = ( Base ‘ 𝐹 )
scaffval.a ⊢ ∙ = ( ·sf ‘ 𝑊 )
scaffval.s ⊢ · = ( ·𝑠 ‘ 𝑊 )
Assertion scafeq ( · Fn ( 𝐾 × 𝐵 ) → ∙ = · )

Proof

Step Hyp Ref Expression
1 scaffval.b ⊢ 𝐵 = ( Base ‘ 𝑊 )
2 scaffval.f ⊢ 𝐹 = ( Scalar ‘ 𝑊 )
3 scaffval.k ⊢ 𝐾 = ( Base ‘ 𝐹 )
4 scaffval.a ⊢ ∙ = ( ·sf ‘ 𝑊 )
5 scaffval.s ⊢ · = ( ·𝑠 ‘ 𝑊 )
6 1 2 3 4 5 scaffval ⊢ ∙ = ( 𝑥 ∈ 𝐾 , 𝑦 ∈ 𝐵 ↦ ( 𝑥 · 𝑦 ) )
7 fnov ⊢ ( · Fn ( 𝐾 × 𝐵 ) ↔ · = ( 𝑥 ∈ 𝐾 , 𝑦 ∈ 𝐵 ↦ ( 𝑥 · 𝑦 ) ) )
8 7 biimpi ⊢ ( · Fn ( 𝐾 × 𝐵 ) → · = ( 𝑥 ∈ 𝐾 , 𝑦 ∈ 𝐵 ↦ ( 𝑥 · 𝑦 ) ) )
9 6 8 eqtr4id ⊢ ( · Fn ( 𝐾 × 𝐵 ) → ∙ = · )