Metamath Proof Explorer


Theorem sinhneg

Description: The sinh function is odd. (Contributed by Jon Pennant, 9-Sep-2026)

Ref Expression
Assertion sinhneg ( 𝐴 ∈ ℂ → ( sinh ‘ - 𝐴 ) = - ( sinh ‘ 𝐴 ) )

Proof

Step Hyp Ref Expression
1 ax-icn ⊢ i ∈ ℂ
2 1 jctl ⊢ ( 𝐴 ∈ ℂ → ( i ∈ ℂ ∧ 𝐴 ∈ ℂ ) )
3 mulcl ⊢ ( ( i ∈ ℂ ∧ 𝐴 ∈ ℂ ) → ( i · 𝐴 ) ∈ ℂ )
4 sincl ⊢ ( ( i · 𝐴 ) ∈ ℂ → ( sin ‘ ( i · 𝐴 ) ) ∈ ℂ )
5 2 3 4 3syl ⊢ ( 𝐴 ∈ ℂ → ( sin ‘ ( i · 𝐴 ) ) ∈ ℂ )
6 1 a1i ⊢ ( 𝐴 ∈ ℂ → i ∈ ℂ )
7 ine0 ⊢ i ≠ 0
8 7 a1i ⊢ ( 𝐴 ∈ ℂ → i ≠ 0 )
9 5 6 8 divnegd ⊢ ( 𝐴 ∈ ℂ → - ( ( sin ‘ ( i · 𝐴 ) ) / i ) = ( - ( sin ‘ ( i · 𝐴 ) ) / i ) )
10 sinhval-named ⊢ ( 𝐴 ∈ ℂ → ( sinh ‘ 𝐴 ) = ( ( sin ‘ ( i · 𝐴 ) ) / i ) )
11 10 negeqd ⊢ ( 𝐴 ∈ ℂ → - ( sinh ‘ 𝐴 ) = - ( ( sin ‘ ( i · 𝐴 ) ) / i ) )
12 negcl ⊢ ( 𝐴 ∈ ℂ → - 𝐴 ∈ ℂ )
13 sinhval-named ⊢ ( - 𝐴 ∈ ℂ → ( sinh ‘ - 𝐴 ) = ( ( sin ‘ ( i · - 𝐴 ) ) / i ) )
14 12 13 syl ⊢ ( 𝐴 ∈ ℂ → ( sinh ‘ - 𝐴 ) = ( ( sin ‘ ( i · - 𝐴 ) ) / i ) )
15 mulneg2 ⊢ ( ( i ∈ ℂ ∧ 𝐴 ∈ ℂ ) → ( i · - 𝐴 ) = - ( i · 𝐴 ) )
16 2 15 syl ⊢ ( 𝐴 ∈ ℂ → ( i · - 𝐴 ) = - ( i · 𝐴 ) )
17 16 eqcomd ⊢ ( 𝐴 ∈ ℂ → - ( i · 𝐴 ) = ( i · - 𝐴 ) )
18 17 fveq2d ⊢ ( 𝐴 ∈ ℂ → ( sin ‘ - ( i · 𝐴 ) ) = ( sin ‘ ( i · - 𝐴 ) ) )
19 18 oveq1d ⊢ ( 𝐴 ∈ ℂ → ( ( sin ‘ - ( i · 𝐴 ) ) / i ) = ( ( sin ‘ ( i · - 𝐴 ) ) / i ) )
20 sinneg ⊢ ( ( i · 𝐴 ) ∈ ℂ → ( sin ‘ - ( i · 𝐴 ) ) = - ( sin ‘ ( i · 𝐴 ) ) )
21 2 3 20 3syl ⊢ ( 𝐴 ∈ ℂ → ( sin ‘ - ( i · 𝐴 ) ) = - ( sin ‘ ( i · 𝐴 ) ) )
22 21 oveq1d ⊢ ( 𝐴 ∈ ℂ → ( ( sin ‘ - ( i · 𝐴 ) ) / i ) = ( - ( sin ‘ ( i · 𝐴 ) ) / i ) )
23 14 19 22 3eqtr2d ⊢ ( 𝐴 ∈ ℂ → ( sinh ‘ - 𝐴 ) = ( - ( sin ‘ ( i · 𝐴 ) ) / i ) )
24 9 11 23 3eqtr4rd ⊢ ( 𝐴 ∈ ℂ → ( sinh ‘ - 𝐴 ) = - ( sinh ‘ 𝐴 ) )