Metamath Proof Explorer


Theorem strb

Description: Strong state theorem (bidirectional version). (Contributed by NM, 7-Apr-2001) (New usage is discouraged.)

Ref Expression
Hypotheses str.1 ⊢ 𝐴 ∈ Cℋ
str.2 ⊢ 𝐵 ∈ Cℋ
Assertion strb ( ∀ 𝑓 ∈ States ( ( 𝑓 ‘ 𝐴 ) = 1 → ( 𝑓 ‘ 𝐵 ) = 1 ) ↔ 𝐴 ⊆ 𝐵 )

Proof

Step Hyp Ref Expression
1 str.1 ⊢ 𝐴 ∈ Cℋ
2 str.2 ⊢ 𝐵 ∈ Cℋ
3 1 2 stri ⊢ ( ∀ 𝑓 ∈ States ( ( 𝑓 ‘ 𝐴 ) = 1 → ( 𝑓 ‘ 𝐵 ) = 1 ) → 𝐴 ⊆ 𝐵 )
4 1 2 stlesi ⊢ ( 𝑓 ∈ States → ( 𝐴 ⊆ 𝐵 → ( ( 𝑓 ‘ 𝐴 ) = 1 → ( 𝑓 ‘ 𝐵 ) = 1 ) ) )
5 4 com12 ⊢ ( 𝐴 ⊆ 𝐵 → ( 𝑓 ∈ States → ( ( 𝑓 ‘ 𝐴 ) = 1 → ( 𝑓 ‘ 𝐵 ) = 1 ) ) )
6 5 ralrimiv ⊢ ( 𝐴 ⊆ 𝐵 → ∀ 𝑓 ∈ States ( ( 𝑓 ‘ 𝐴 ) = 1 → ( 𝑓 ‘ 𝐵 ) = 1 ) )
7 3 6 impbii ⊢ ( ∀ 𝑓 ∈ States ( ( 𝑓 ‘ 𝐴 ) = 1 → ( 𝑓 ‘ 𝐵 ) = 1 ) ↔ 𝐴 ⊆ 𝐵 )