Metamath Proof Explorer


Theorem strlem6

Description: Lemma for strong state theorem. (Contributed by NM, 2-Nov-1999) (New usage is discouraged.)

Ref Expression
Hypotheses strlem3.1 ⊢ 𝑆 = ( 𝑥 ∈ Cℋ ↦ ( ( normℎ ‘ ( ( projℎ ‘ 𝑥 ) ‘ 𝑢 ) ) ↑ 2 ) )
strlem3.2 ⊢ ( 𝜑 ↔ ( 𝑢 ∈ ( 𝐴 ∖ 𝐵 ) ∧ ( normℎ ‘ 𝑢 ) = 1 ) )
strlem3.3 ⊢ 𝐴 ∈ Cℋ
strlem3.4 ⊢ 𝐵 ∈ Cℋ
Assertion strlem6 ( 𝜑 → ¬ ( ( 𝑆 ‘ 𝐴 ) = 1 → ( 𝑆 ‘ 𝐵 ) = 1 ) )

Proof

Step Hyp Ref Expression
1 strlem3.1 ⊢ 𝑆 = ( 𝑥 ∈ Cℋ ↦ ( ( normℎ ‘ ( ( projℎ ‘ 𝑥 ) ‘ 𝑢 ) ) ↑ 2 ) )
2 strlem3.2 ⊢ ( 𝜑 ↔ ( 𝑢 ∈ ( 𝐴 ∖ 𝐵 ) ∧ ( normℎ ‘ 𝑢 ) = 1 ) )
3 strlem3.3 ⊢ 𝐴 ∈ Cℋ
4 strlem3.4 ⊢ 𝐵 ∈ Cℋ
5 1 2 3 4 strlem4 ⊢ ( 𝜑 → ( 𝑆 ‘ 𝐴 ) = 1 )
6 1 2 3 4 strlem3 ⊢ ( 𝜑 → 𝑆 ∈ States )
7 stcl ⊢ ( 𝑆 ∈ States → ( 𝐵 ∈ Cℋ → ( 𝑆 ‘ 𝐵 ) ∈ ℝ ) )
8 6 4 7 mpisyl ⊢ ( 𝜑 → ( 𝑆 ‘ 𝐵 ) ∈ ℝ )
9 1 2 3 4 strlem5 ⊢ ( 𝜑 → ( 𝑆 ‘ 𝐵 ) < 1 )
10 8 9 ltned ⊢ ( 𝜑 → ( 𝑆 ‘ 𝐵 ) ≠ 1 )
11 10 neneqd ⊢ ( 𝜑 → ¬ ( 𝑆 ‘ 𝐵 ) = 1 )
12 5 11 jcnd ⊢ ( 𝜑 → ¬ ( ( 𝑆 ‘ 𝐴 ) = 1 → ( 𝑆 ‘ 𝐵 ) = 1 ) )