Metamath Proof Explorer


Theorem subtr2

Description: Transitivity of implicit substitution into a wff. (Contributed by Jeff Hankins, 19-Sep-2009) (Proof shortened by Mario Carneiro, 11-Dec-2016)

Ref Expression
Hypotheses subtr.1 ⊢ Ⅎ 𝑥 𝐴
subtr.2 ⊢ Ⅎ 𝑥 𝐵
subtr2.3 ⊢ Ⅎ 𝑥 𝜓
subtr2.4 ⊢ Ⅎ 𝑥 𝜒
subtr2.5 ⊢ ( 𝑥 = 𝐴 → ( 𝜑 ↔ 𝜓 ) )
subtr2.6 ⊢ ( 𝑥 = 𝐵 → ( 𝜑 ↔ 𝜒 ) )
Assertion subtr2 ( ( 𝐴 ∈ 𝐶 ∧ 𝐵 ∈ 𝐷 ) → ( 𝐴 = 𝐵 → ( 𝜓 ↔ 𝜒 ) ) )

Proof

Step Hyp Ref Expression
1 subtr.1 ⊢ Ⅎ 𝑥 𝐴
2 subtr.2 ⊢ Ⅎ 𝑥 𝐵
3 subtr2.3 ⊢ Ⅎ 𝑥 𝜓
4 subtr2.4 ⊢ Ⅎ 𝑥 𝜒
5 subtr2.5 ⊢ ( 𝑥 = 𝐴 → ( 𝜑 ↔ 𝜓 ) )
6 subtr2.6 ⊢ ( 𝑥 = 𝐵 → ( 𝜑 ↔ 𝜒 ) )
7 1 2 nfeq ⊢ Ⅎ 𝑥 𝐴 = 𝐵
8 3 4 nfbi ⊢ Ⅎ 𝑥 ( 𝜓 ↔ 𝜒 )
9 7 8 nfim ⊢ Ⅎ 𝑥 ( 𝐴 = 𝐵 → ( 𝜓 ↔ 𝜒 ) )
10 eqeq1 ⊢ ( 𝑥 = 𝐴 → ( 𝑥 = 𝐵 ↔ 𝐴 = 𝐵 ) )
11 5 bibi1d ⊢ ( 𝑥 = 𝐴 → ( ( 𝜑 ↔ 𝜒 ) ↔ ( 𝜓 ↔ 𝜒 ) ) )
12 10 11 imbi12d ⊢ ( 𝑥 = 𝐴 → ( ( 𝑥 = 𝐵 → ( 𝜑 ↔ 𝜒 ) ) ↔ ( 𝐴 = 𝐵 → ( 𝜓 ↔ 𝜒 ) ) ) )
13 1 9 12 6 vtoclgf ⊢ ( 𝐴 ∈ 𝐶 → ( 𝐴 = 𝐵 → ( 𝜓 ↔ 𝜒 ) ) )
14 13 adantr ⊢ ( ( 𝐴 ∈ 𝐶 ∧ 𝐵 ∈ 𝐷 ) → ( 𝐴 = 𝐵 → ( 𝜓 ↔ 𝜒 ) ) )