Metamath Proof Explorer


Theorem swoso

Description: If the incomparability relation is equivalent to equality in a subset, then the partial order strictly orders the subset. (Contributed by Mario Carneiro, 30-Dec-2014)

Ref Expression
Hypotheses swoer.1 ⊢ 𝑅 = ( ( 𝑋 × 𝑋 ) ∖ ( < ∪ ◡ < ) )
swoer.2 ⊢ ( ( 𝜑 ∧ ( 𝑦 ∈ 𝑋 ∧ 𝑧 ∈ 𝑋 ) ) → ( 𝑦 < 𝑧 → ¬ 𝑧 < 𝑦 ) )
swoer.3 ⊢ ( ( 𝜑 ∧ ( 𝑥 ∈ 𝑋 ∧ 𝑦 ∈ 𝑋 ∧ 𝑧 ∈ 𝑋 ) ) → ( 𝑥 < 𝑦 → ( 𝑥 < 𝑧 ∨ 𝑧 < 𝑦 ) ) )
swoso.4 ⊢ ( 𝜑 → 𝑌 ⊆ 𝑋 )
swoso.5 ⊢ ( ( 𝜑 ∧ ( 𝑥 ∈ 𝑌 ∧ 𝑦 ∈ 𝑌 ∧ 𝑥 𝑅 𝑦 ) ) → 𝑥 = 𝑦 )
Assertion swoso ( 𝜑 → < Or 𝑌 )

Proof

Step Hyp Ref Expression
1 swoer.1 ⊢ 𝑅 = ( ( 𝑋 × 𝑋 ) ∖ ( < ∪ ◡ < ) )
2 swoer.2 ⊢ ( ( 𝜑 ∧ ( 𝑦 ∈ 𝑋 ∧ 𝑧 ∈ 𝑋 ) ) → ( 𝑦 < 𝑧 → ¬ 𝑧 < 𝑦 ) )
3 swoer.3 ⊢ ( ( 𝜑 ∧ ( 𝑥 ∈ 𝑋 ∧ 𝑦 ∈ 𝑋 ∧ 𝑧 ∈ 𝑋 ) ) → ( 𝑥 < 𝑦 → ( 𝑥 < 𝑧 ∨ 𝑧 < 𝑦 ) ) )
4 swoso.4 ⊢ ( 𝜑 → 𝑌 ⊆ 𝑋 )
5 swoso.5 ⊢ ( ( 𝜑 ∧ ( 𝑥 ∈ 𝑌 ∧ 𝑦 ∈ 𝑌 ∧ 𝑥 𝑅 𝑦 ) ) → 𝑥 = 𝑦 )
6 2 3 swopo ⊢ ( 𝜑 → < Po 𝑋 )
7 poss ⊢ ( 𝑌 ⊆ 𝑋 → ( < Po 𝑋 → < Po 𝑌 ) )
8 4 6 7 sylc ⊢ ( 𝜑 → < Po 𝑌 )
9 4 sselda ⊢ ( ( 𝜑 ∧ 𝑥 ∈ 𝑌 ) → 𝑥 ∈ 𝑋 )
10 4 sselda ⊢ ( ( 𝜑 ∧ 𝑦 ∈ 𝑌 ) → 𝑦 ∈ 𝑋 )
11 9 10 anim12dan ⊢ ( ( 𝜑 ∧ ( 𝑥 ∈ 𝑌 ∧ 𝑦 ∈ 𝑌 ) ) → ( 𝑥 ∈ 𝑋 ∧ 𝑦 ∈ 𝑋 ) )
12 1 brdifun ⊢ ( ( 𝑥 ∈ 𝑋 ∧ 𝑦 ∈ 𝑋 ) → ( 𝑥 𝑅 𝑦 ↔ ¬ ( 𝑥 < 𝑦 ∨ 𝑦 < 𝑥 ) ) )
13 11 12 syl ⊢ ( ( 𝜑 ∧ ( 𝑥 ∈ 𝑌 ∧ 𝑦 ∈ 𝑌 ) ) → ( 𝑥 𝑅 𝑦 ↔ ¬ ( 𝑥 < 𝑦 ∨ 𝑦 < 𝑥 ) ) )
14 df-3an ⊢ ( ( 𝑥 ∈ 𝑌 ∧ 𝑦 ∈ 𝑌 ∧ 𝑥 𝑅 𝑦 ) ↔ ( ( 𝑥 ∈ 𝑌 ∧ 𝑦 ∈ 𝑌 ) ∧ 𝑥 𝑅 𝑦 ) )
15 14 5 sylan2br ⊢ ( ( 𝜑 ∧ ( ( 𝑥 ∈ 𝑌 ∧ 𝑦 ∈ 𝑌 ) ∧ 𝑥 𝑅 𝑦 ) ) → 𝑥 = 𝑦 )
16 15 expr ⊢ ( ( 𝜑 ∧ ( 𝑥 ∈ 𝑌 ∧ 𝑦 ∈ 𝑌 ) ) → ( 𝑥 𝑅 𝑦 → 𝑥 = 𝑦 ) )
17 13 16 sylbird ⊢ ( ( 𝜑 ∧ ( 𝑥 ∈ 𝑌 ∧ 𝑦 ∈ 𝑌 ) ) → ( ¬ ( 𝑥 < 𝑦 ∨ 𝑦 < 𝑥 ) → 𝑥 = 𝑦 ) )
18 17 orrd ⊢ ( ( 𝜑 ∧ ( 𝑥 ∈ 𝑌 ∧ 𝑦 ∈ 𝑌 ) ) → ( ( 𝑥 < 𝑦 ∨ 𝑦 < 𝑥 ) ∨ 𝑥 = 𝑦 ) )
19 3orcomb ⊢ ( ( 𝑥 < 𝑦 ∨ 𝑥 = 𝑦 ∨ 𝑦 < 𝑥 ) ↔ ( 𝑥 < 𝑦 ∨ 𝑦 < 𝑥 ∨ 𝑥 = 𝑦 ) )
20 df-3or ⊢ ( ( 𝑥 < 𝑦 ∨ 𝑦 < 𝑥 ∨ 𝑥 = 𝑦 ) ↔ ( ( 𝑥 < 𝑦 ∨ 𝑦 < 𝑥 ) ∨ 𝑥 = 𝑦 ) )
21 19 20 bitri ⊢ ( ( 𝑥 < 𝑦 ∨ 𝑥 = 𝑦 ∨ 𝑦 < 𝑥 ) ↔ ( ( 𝑥 < 𝑦 ∨ 𝑦 < 𝑥 ) ∨ 𝑥 = 𝑦 ) )
22 18 21 sylibr ⊢ ( ( 𝜑 ∧ ( 𝑥 ∈ 𝑌 ∧ 𝑦 ∈ 𝑌 ) ) → ( 𝑥 < 𝑦 ∨ 𝑥 = 𝑦 ∨ 𝑦 < 𝑥 ) )
23 8 22 issod ⊢ ( 𝜑 → < Or 𝑌 )