Metamath Proof Explorer


Theorem tposres0

Description: The transposition of a set restricted to the empty set is the set restricted to the empty set. See also ressn and dftpos6 for an alternate proof. (Contributed by Zhi Wang, 6-Oct-2025)

Ref Expression
Assertion tposres0 ( tpos 𝐹 ↾ { ∅ } ) = ( 𝐹 ↾ { ∅ } )

Proof

Step Hyp Ref Expression
1 relres ⊢ Rel ( tpos 𝐹 ↾ { ∅ } )
2 relres ⊢ Rel ( 𝐹 ↾ { ∅ } )
3 velsn ⊢ ( 𝑥 ∈ { ∅ } ↔ 𝑥 = ∅ )
4 brtpos0 ⊢ ( 𝑦 ∈ V → ( ∅ tpos 𝐹 𝑦 ↔ ∅ 𝐹 𝑦 ) )
5 4 elv ⊢ ( ∅ tpos 𝐹 𝑦 ↔ ∅ 𝐹 𝑦 )
6 breq1 ⊢ ( 𝑥 = ∅ → ( 𝑥 tpos 𝐹 𝑦 ↔ ∅ tpos 𝐹 𝑦 ) )
7 breq1 ⊢ ( 𝑥 = ∅ → ( 𝑥 𝐹 𝑦 ↔ ∅ 𝐹 𝑦 ) )
8 6 7 bibi12d ⊢ ( 𝑥 = ∅ → ( ( 𝑥 tpos 𝐹 𝑦 ↔ 𝑥 𝐹 𝑦 ) ↔ ( ∅ tpos 𝐹 𝑦 ↔ ∅ 𝐹 𝑦 ) ) )
9 5 8 mpbiri ⊢ ( 𝑥 = ∅ → ( 𝑥 tpos 𝐹 𝑦 ↔ 𝑥 𝐹 𝑦 ) )
10 3 9 sylbi ⊢ ( 𝑥 ∈ { ∅ } → ( 𝑥 tpos 𝐹 𝑦 ↔ 𝑥 𝐹 𝑦 ) )
11 10 pm5.32i ⊢ ( ( 𝑥 ∈ { ∅ } ∧ 𝑥 tpos 𝐹 𝑦 ) ↔ ( 𝑥 ∈ { ∅ } ∧ 𝑥 𝐹 𝑦 ) )
12 vex ⊢ 𝑦 ∈ V
13 12 brresi ⊢ ( 𝑥 ( tpos 𝐹 ↾ { ∅ } ) 𝑦 ↔ ( 𝑥 ∈ { ∅ } ∧ 𝑥 tpos 𝐹 𝑦 ) )
14 12 brresi ⊢ ( 𝑥 ( 𝐹 ↾ { ∅ } ) 𝑦 ↔ ( 𝑥 ∈ { ∅ } ∧ 𝑥 𝐹 𝑦 ) )
15 11 13 14 3bitr4i ⊢ ( 𝑥 ( tpos 𝐹 ↾ { ∅ } ) 𝑦 ↔ 𝑥 ( 𝐹 ↾ { ∅ } ) 𝑦 )
16 1 2 15 eqbrriv ⊢ ( tpos 𝐹 ↾ { ∅ } ) = ( 𝐹 ↾ { ∅ } )