Metamath Proof Explorer


Theorem ussid

Description: In case the base of the UnifSt element of the uniform space is the base of its element structure, then UnifSt does not restrict it further. (Contributed by Thierry Arnoux, 4-Dec-2017)

Ref Expression
Hypotheses ussval.1 ⊢ 𝐵 = ( Base ‘ 𝑊 )
ussval.2 ⊢ 𝑈 = ( UnifSet ‘ 𝑊 )
Assertion ussid ( ( 𝐵 × 𝐵 ) = ∪ 𝑈 → 𝑈 = ( UnifSt ‘ 𝑊 ) )

Proof

Step Hyp Ref Expression
1 ussval.1 ⊢ 𝐵 = ( Base ‘ 𝑊 )
2 ussval.2 ⊢ 𝑈 = ( UnifSet ‘ 𝑊 )
3 oveq2 ⊢ ( ( 𝐵 × 𝐵 ) = ∪ 𝑈 → ( 𝑈 ↾t ( 𝐵 × 𝐵 ) ) = ( 𝑈 ↾t ∪ 𝑈 ) )
4 id ⊢ ( ( 𝐵 × 𝐵 ) = ∪ 𝑈 → ( 𝐵 × 𝐵 ) = ∪ 𝑈 )
5 1 fvexi ⊢ 𝐵 ∈ V
6 5 5 xpex ⊢ ( 𝐵 × 𝐵 ) ∈ V
7 4 6 eqeltrrdi ⊢ ( ( 𝐵 × 𝐵 ) = ∪ 𝑈 → ∪ 𝑈 ∈ V )
8 uniexb ⊢ ( 𝑈 ∈ V ↔ ∪ 𝑈 ∈ V )
9 7 8 sylibr ⊢ ( ( 𝐵 × 𝐵 ) = ∪ 𝑈 → 𝑈 ∈ V )
10 eqid ⊢ ∪ 𝑈 = ∪ 𝑈
11 10 restid ⊢ ( 𝑈 ∈ V → ( 𝑈 ↾t ∪ 𝑈 ) = 𝑈 )
12 9 11 syl ⊢ ( ( 𝐵 × 𝐵 ) = ∪ 𝑈 → ( 𝑈 ↾t ∪ 𝑈 ) = 𝑈 )
13 3 12 eqtr2d ⊢ ( ( 𝐵 × 𝐵 ) = ∪ 𝑈 → 𝑈 = ( 𝑈 ↾t ( 𝐵 × 𝐵 ) ) )
14 1 2 ussval ⊢ ( 𝑈 ↾t ( 𝐵 × 𝐵 ) ) = ( UnifSt ‘ 𝑊 )
15 13 14 eqtrdi ⊢ ( ( 𝐵 × 𝐵 ) = ∪ 𝑈 → 𝑈 = ( UnifSt ‘ 𝑊 ) )