Metamath Proof Explorer


Theorem vvin

Description: Two classes are both the universal class if and only if their intersection is the universal class. Dual of un00 . (Contributed by BJ, 12-Jul-2026)

Ref Expression
Assertion vvin ( ( 𝐴 = V ∧ 𝐵 = V ) ↔ ( 𝐴 ∩ 𝐵 ) = V )

Proof

Step Hyp Ref Expression
1 ineq12 ⊢ ( ( 𝐴 = V ∧ 𝐵 = V ) → ( 𝐴 ∩ 𝐵 ) = ( V ∩ V ) )
2 inv1 ⊢ ( V ∩ V ) = V
3 1 2 eqtrdi ⊢ ( ( 𝐴 = V ∧ 𝐵 = V ) → ( 𝐴 ∩ 𝐵 ) = V )
4 inss1 ⊢ ( 𝐴 ∩ 𝐵 ) ⊆ 𝐴
5 sseq1 ⊢ ( ( 𝐴 ∩ 𝐵 ) = V → ( ( 𝐴 ∩ 𝐵 ) ⊆ 𝐴 ↔ V ⊆ 𝐴 ) )
6 4 5 mpbii ⊢ ( ( 𝐴 ∩ 𝐵 ) = V → V ⊆ 𝐴 )
7 vss ⊢ ( V ⊆ 𝐴 ↔ 𝐴 = V )
8 6 7 sylib ⊢ ( ( 𝐴 ∩ 𝐵 ) = V → 𝐴 = V )
9 inss2 ⊢ ( 𝐴 ∩ 𝐵 ) ⊆ 𝐵
10 sseq1 ⊢ ( ( 𝐴 ∩ 𝐵 ) = V → ( ( 𝐴 ∩ 𝐵 ) ⊆ 𝐵 ↔ V ⊆ 𝐵 ) )
11 9 10 mpbii ⊢ ( ( 𝐴 ∩ 𝐵 ) = V → V ⊆ 𝐵 )
12 vss ⊢ ( V ⊆ 𝐵 ↔ 𝐵 = V )
13 11 12 sylib ⊢ ( ( 𝐴 ∩ 𝐵 ) = V → 𝐵 = V )
14 8 13 jca ⊢ ( ( 𝐴 ∩ 𝐵 ) = V → ( 𝐴 = V ∧ 𝐵 = V ) )
15 3 14 impbii ⊢ ( ( 𝐴 = V ∧ 𝐵 = V ) ↔ ( 𝐴 ∩ 𝐵 ) = V )