Metamath Proof Explorer


Theorem wl-equsalcom

Description: This simple equivalence eases substitution of one expression for the other. (Contributed by Wolf Lammen, 1-Sep-2018)

Ref Expression
Assertion wl-equsalcom ( ∀ 𝑥 ( 𝑥 = 𝑦 → 𝜑 ) ↔ ∀ 𝑥 ( 𝑦 = 𝑥 → 𝜑 ) )

Proof

Step Hyp Ref Expression
1 equcom ⊢ ( 𝑥 = 𝑦 ↔ 𝑦 = 𝑥 )
2 1 imbi1i ⊢ ( ( 𝑥 = 𝑦 → 𝜑 ) ↔ ( 𝑦 = 𝑥 → 𝜑 ) )
3 2 albii ⊢ ( ∀ 𝑥 ( 𝑥 = 𝑦 → 𝜑 ) ↔ ∀ 𝑥 ( 𝑦 = 𝑥 → 𝜑 ) )