Metamath Proof Explorer


Theorem cbvoprab1davw

Description: Change the first bound variable in an operation abstraction. Deduction form. (Contributed by GG, 14-Aug-2025)

Ref Expression
Hypothesis cbvoprab1davw.1
|- ( ( ph /\ x = w ) -> ( ps <-> ch ) )
Assertion cbvoprab1davw
|- ( ph -> { <. <. x , y >. , z >. | ps } = { <. <. w , y >. , z >. | ch } )

Proof

Step Hyp Ref Expression
1 cbvoprab1davw.1
 |-  ( ( ph /\ x = w ) -> ( ps <-> ch ) )
2 opeq1
 |-  ( x = w -> <. x , y >. = <. w , y >. )
3 2 adantl
 |-  ( ( ph /\ x = w ) -> <. x , y >. = <. w , y >. )
4 3 opeq1d
 |-  ( ( ph /\ x = w ) -> <. <. x , y >. , z >. = <. <. w , y >. , z >. )
5 4 eqeq2d
 |-  ( ( ph /\ x = w ) -> ( t = <. <. x , y >. , z >. <-> t = <. <. w , y >. , z >. ) )
6 5 1 anbi12d
 |-  ( ( ph /\ x = w ) -> ( ( t = <. <. x , y >. , z >. /\ ps ) <-> ( t = <. <. w , y >. , z >. /\ ch ) ) )
7 6 2exbidv
 |-  ( ( ph /\ x = w ) -> ( E. y E. z ( t = <. <. x , y >. , z >. /\ ps ) <-> E. y E. z ( t = <. <. w , y >. , z >. /\ ch ) ) )
8 7 cbvexdvaw
 |-  ( ph -> ( E. x E. y E. z ( t = <. <. x , y >. , z >. /\ ps ) <-> E. w E. y E. z ( t = <. <. w , y >. , z >. /\ ch ) ) )
9 8 abbidv
 |-  ( ph -> { t | E. x E. y E. z ( t = <. <. x , y >. , z >. /\ ps ) } = { t | E. w E. y E. z ( t = <. <. w , y >. , z >. /\ ch ) } )
10 df-oprab
 |-  { <. <. x , y >. , z >. | ps } = { t | E. x E. y E. z ( t = <. <. x , y >. , z >. /\ ps ) }
11 df-oprab
 |-  { <. <. w , y >. , z >. | ch } = { t | E. w E. y E. z ( t = <. <. w , y >. , z >. /\ ch ) }
12 9 10 11 3eqtr4g
 |-  ( ph -> { <. <. x , y >. , z >. | ps } = { <. <. w , y >. , z >. | ch } )