Metamath Proof Explorer


Theorem csbied

Description: Conversion of implicit substitution to explicit substitution into a class. (Contributed by Mario Carneiro, 2-Dec-2014) (Revised by Mario Carneiro, 13-Oct-2016)

Ref Expression
Hypotheses csbied.1
|- ( ph -> A e. V )
csbied.2
|- ( ( ph /\ x = A ) -> B = C )
Assertion csbied
|- ( ph -> [_ A / x ]_ B = C )

Proof

Step Hyp Ref Expression
1 csbied.1
 |-  ( ph -> A e. V )
2 csbied.2
 |-  ( ( ph /\ x = A ) -> B = C )
3 nfv
 |-  F/ x ph
4 nfcvd
 |-  ( ph -> F/_ x C )
5 3 4 1 2 csbiedf
 |-  ( ph -> [_ A / x ]_ B = C )