Theorem rexabsod

Description: Deduction form of rexabso . (Contributed by Eric Schmidt, 19-Oct-2025)

	Ref	Expression
Hypothesis	ralabsod.1	|- ( ph -> Tr M )
Assertion	rexabsod	|- ( ( ph /\ A e. M ) -> ( E. x e. A ps <-> E. x e. M ( x e. A /\ ps ) ) )

Proof

Step	Hyp	Ref	Expression
1		ralabsod.1	|- ( ph -> Tr M )
2		rexabso	|- ( ( Tr M /\ A e. M ) -> ( E. x e. A ps <-> E. x e. M ( x e. A /\ ps ) ) )
3	1 2	sylan	|- ( ( ph /\ A e. M ) -> ( E. x e. A ps <-> E. x e. M ( x e. A /\ ps ) ) )