Metamath Proof Explorer


Theorem stdpc4

Description: The specialization axiom of standard predicate calculus. It states that if a statement ph holds for all x , then it also holds for the specific case of t (properly) substituted for x . Translated to traditional notation, it can be read: " A. x ph ( x ) -> ph ( t ) , provided that t is free for x in ph ( x ) ". Axiom 4 of Mendelson p. 69. See also spsbc and rspsbc . (Contributed by NM, 14-May-1993) Revise df-sb . (Revised by BJ, 22-Dec-2020)

Ref Expression
Assertion stdpc4
|- ( A. x ph -> [ t / x ] ph )

Proof

Step Hyp Ref Expression
1 ala1
 |-  ( A. x ph -> A. x ( x = y -> ph ) )
2 1 a1d
 |-  ( A. x ph -> ( y = t -> A. x ( x = y -> ph ) ) )
3 2 alrimiv
 |-  ( A. x ph -> A. y ( y = t -> A. x ( x = y -> ph ) ) )
4 df-sb
 |-  ( [ t / x ] ph <-> A. y ( y = t -> A. x ( x = y -> ph ) ) )
5 3 4 sylibr
 |-  ( A. x ph -> [ t / x ] ph )