Metamath Proof Explorer


Theorem 12lcm5e60

Description: The lcm of 12 and 5 is 60. (Contributed by metakunt, 25-Apr-2024)

Ref Expression
Assertion 12lcm5e60 ⊢ 12 lcm 5 = 60

Proof

Step Hyp Ref Expression
1 1nn0 ⊢ 1 ∈ ℕ 0
2 2nn ⊢ 2 ∈ ℕ
3 1 2 decnncl ⊢ 12 ∈ ℕ
4 5nn ⊢ 5 ∈ ℕ
5 1nn ⊢ 1 ∈ ℕ
6 6nn ⊢ 6 ∈ ℕ
7 6 decnncl2 ⊢ 60 ∈ ℕ
8 12gcd5e1 ⊢ 12 gcd 5 = 1
9 6nn0 ⊢ 6 ∈ ℕ 0
10 0nn0 ⊢ 0 ∈ ℕ 0
11 9 10 deccl ⊢ 60 ∈ ℕ 0
12 11 nn0cni ⊢ 60 ∈ ℂ
13 12 mullidi ⊢ 1 ⋅ 60 = 60
14 5nn0 ⊢ 5 ∈ ℕ 0
15 2nn0 ⊢ 2 ∈ ℕ 0
16 eqid ⊢ 12 = 12
17 5cn ⊢ 5 ∈ ℂ
18 17 mullidi ⊢ 1 ⋅ 5 = 5
19 18 oveq1i ⊢ 1 ⋅ 5 + 1 = 5 + 1
20 5p1e6 ⊢ 5 + 1 = 6
21 19 20 eqtri ⊢ 1 ⋅ 5 + 1 = 6
22 2cn ⊢ 2 ∈ ℂ
23 5t2e10 ⊢ 5 ⋅ 2 = 10
24 17 22 23 mulcomli ⊢ 2 ⋅ 5 = 10
25 14 1 15 16 10 1 21 24 decmul1c ⊢ 12 ⋅ 5 = 60
26 3 4 5 7 8 13 25 lcmeprodgcdi ⊢ 12 lcm 5 = 60