Metamath Proof Explorer


Theorem 3oalem5

Description: Lemma for 3OA (weak) orthoarguesian law. (Contributed by NM, 19-Oct-1999) (New usage is discouraged.)

Ref Expression
Hypotheses 3oa.1 ⊢ A ∈ C ℋ
3oa.2 ⊢ B ∈ C ℋ
3oa.3 ⊢ C ∈ C ℋ
3oa.4 ⊢ R = ⊥ ⁡ B ∩ B ∨ ℋ A
3oa.5 ⊢ S = ⊥ ⁡ C ∩ C ∨ ℋ A
Assertion 3oalem5 ⊢ B + ℋ R ∩ C + ℋ S = B ∨ ℋ R ∩ C ∨ ℋ S

Proof

Step Hyp Ref Expression
1 3oa.1 ⊢ A ∈ C ℋ
2 3oa.2 ⊢ B ∈ C ℋ
3 3oa.3 ⊢ C ∈ C ℋ
4 3oa.4 ⊢ R = ⊥ ⁡ B ∩ B ∨ ℋ A
5 3oa.5 ⊢ S = ⊥ ⁡ C ∩ C ∨ ℋ A
6 4 3oalem4 ⊢ R ⊆ ⊥ ⁡ B
7 2 choccli ⊢ ⊥ ⁡ B ∈ C ℋ
8 2 1 chjcli ⊢ B ∨ ℋ A ∈ C ℋ
9 7 8 chincli ⊢ ⊥ ⁡ B ∩ B ∨ ℋ A ∈ C ℋ
10 4 9 eqeltri ⊢ R ∈ C ℋ
11 10 2 osumi ⊢ R ⊆ ⊥ ⁡ B → R + ℋ B = R ∨ ℋ B
12 6 11 ax-mp ⊢ R + ℋ B = R ∨ ℋ B
13 2 chshii ⊢ B ∈ S ℋ
14 10 chshii ⊢ R ∈ S ℋ
15 13 14 shscomi ⊢ B + ℋ R = R + ℋ B
16 2 10 chjcomi ⊢ B ∨ ℋ R = R ∨ ℋ B
17 12 15 16 3eqtr4i ⊢ B + ℋ R = B ∨ ℋ R
18 5 3oalem4 ⊢ S ⊆ ⊥ ⁡ C
19 3 choccli ⊢ ⊥ ⁡ C ∈ C ℋ
20 3 1 chjcli ⊢ C ∨ ℋ A ∈ C ℋ
21 19 20 chincli ⊢ ⊥ ⁡ C ∩ C ∨ ℋ A ∈ C ℋ
22 5 21 eqeltri ⊢ S ∈ C ℋ
23 22 3 osumi ⊢ S ⊆ ⊥ ⁡ C → S + ℋ C = S ∨ ℋ C
24 18 23 ax-mp ⊢ S + ℋ C = S ∨ ℋ C
25 3 chshii ⊢ C ∈ S ℋ
26 22 chshii ⊢ S ∈ S ℋ
27 25 26 shscomi ⊢ C + ℋ S = S + ℋ C
28 3 22 chjcomi ⊢ C ∨ ℋ S = S ∨ ℋ C
29 24 27 28 3eqtr4i ⊢ C + ℋ S = C ∨ ℋ S
30 17 29 ineq12i ⊢ B + ℋ R ∩ C + ℋ S = B ∨ ℋ R ∩ C ∨ ℋ S