Description: Whenever there are at least 4 atoms under P .\/ Q (specifically,
P , Q , r , and ( P .\/ Q ) ./\ W ), there are also at
least 4 atoms under P .\/ S . This proves the statement in Lemma E
of Crawley p. 114, last line, "...p \/ q/0 and hence p \/ s/0
contains at least four atoms..." Note that by cvlsupr2 , our
( P .\/ r ) = ( Q .\/ r ) is a shorter way to express
r =/= P /\ r =/= Q /\ r .<_ ( P .\/ Q ) . With a longer proof, the
condition -. S .<_ ( P .\/ Q ) could be eliminated (see 4atex ),
although for some purposes this more restricted lemma may be adequate.
(Contributed by NM, 25-Nov-2012)