Metamath Proof Explorer


Theorem abv1

Description: The absolute value of one is one in a division ring. (Contributed by Mario Carneiro, 8-Sep-2014)

Ref Expression
Hypotheses abv0.a ⊢ A = AbsVal ⁡ R
abv1.p ⊢ 1 ˙ = 1 R
Assertion abv1 ⊢ R ∈ DivRing ∧ F ∈ A → F ⁡ 1 ˙ = 1

Proof

Step Hyp Ref Expression
1 abv0.a ⊢ A = AbsVal ⁡ R
2 abv1.p ⊢ 1 ˙ = 1 R
3 id ⊢ F ∈ A → F ∈ A
4 eqid ⊢ 0 R = 0 R
5 4 2 drngunz ⊢ R ∈ DivRing → 1 ˙ ≠ 0 R
6 1 2 4 abv1z ⊢ F ∈ A ∧ 1 ˙ ≠ 0 R → F ⁡ 1 ˙ = 1
7 3 5 6 syl2anr ⊢ R ∈ DivRing ∧ F ∈ A → F ⁡ 1 ˙ = 1