Metamath Proof Explorer


Theorem aiotaint

Description: This is to df-aiota what iotauni is to df-iota (it uses intersection like df-aiota , similar to iotauni using union like df-iota ; we could also prove an analogous result using union here too, in the same way that we have iotaint ). (Contributed by BJ, 31-Aug-2024)

Ref Expression
Assertion aiotaint ∃! x φ ι = x | φ

Proof

Step Hyp Ref Expression
1 reuaiotaiota ∃! x φ ι x | φ = ι
2 1 biimpi ∃! x φ ι x | φ = ι
3 iotaint ∃! x φ ι x | φ = x | φ
4 2 3 eqtr3d ∃! x φ ι = x | φ