Metamath Proof Explorer


Theorem aoprssdm

Description: Domain of closure of an operation. In contrast to oprssdm , no additional property for S ( -. (/) e. S ) is required! (Contributed by Alexander van der Vekens, 26-May-2017)

Ref Expression
Hypothesis aoprssdm.1 ⊢ x ∈ S ∧ y ∈ S → x F y ∈ S
Assertion aoprssdm ⊢ S × S ⊆ dom ⁡ F

Proof

Step Hyp Ref Expression
1 aoprssdm.1 ⊢ x ∈ S ∧ y ∈ S → x F y ∈ S
2 relxp ⊢ Rel ⁡ S × S
3 opelxp ⊢ x y ∈ S × S ↔ x ∈ S ∧ y ∈ S
4 df-aov ⊢ x F y = F ''' x y
5 4 1 eqeltrrid ⊢ x ∈ S ∧ y ∈ S → F ''' x y ∈ S
6 afvvdm ⊢ F ''' x y ∈ S → x y ∈ dom ⁡ F
7 5 6 syl ⊢ x ∈ S ∧ y ∈ S → x y ∈ dom ⁡ F
8 3 7 sylbi ⊢ x y ∈ S × S → x y ∈ dom ⁡ F
9 2 8 relssi ⊢ S × S ⊆ dom ⁡ F