Metamath Proof Explorer


Theorem aspssid

Description: A set of vectors is a subset of its span. ( spanss2 analog.) (Contributed by Mario Carneiro, 7-Jan-2015)

Ref Expression
Hypotheses aspval.a ⊢ A = AlgSpan ⁡ W
aspval.v ⊢ V = Base W
Assertion aspssid ⊢ W ∈ AssAlg ∧ S ⊆ V → S ⊆ A ⁡ S

Proof

Step Hyp Ref Expression
1 aspval.a ⊢ A = AlgSpan ⁡ W
2 aspval.v ⊢ V = Base W
3 ssintub ⊢ S ⊆ ⋂ t ∈ SubRing ⁡ W ∩ LSubSp ⁡ W | S ⊆ t
4 eqid ⊢ LSubSp ⁡ W = LSubSp ⁡ W
5 1 2 4 aspval ⊢ W ∈ AssAlg ∧ S ⊆ V → A ⁡ S = ⋂ t ∈ SubRing ⁡ W ∩ LSubSp ⁡ W | S ⊆ t
6 3 5 sseqtrrid ⊢ W ∈ AssAlg ∧ S ⊆ V → S ⊆ A ⁡ S