Metamath Proof Explorer


Theorem ax12inda2ALT

Description: Alternate proof of ax12inda2 , slightly more direct and not requiring ax-c16 . (Contributed by NM, 4-May-2007) (Proof modification is discouraged.) (New usage is discouraged.)

Ref Expression
Hypothesis ax12inda2.1 ⊢ ¬ ∀ x x = y → x = y → φ → ∀ x x = y → φ
Assertion ax12inda2ALT ⊢ ¬ ∀ x x = y → x = y → ∀ z φ → ∀ x x = y → ∀ z φ

Proof

Step Hyp Ref Expression
1 ax12inda2.1 ⊢ ¬ ∀ x x = y → x = y → φ → ∀ x x = y → φ
2 ax-1 ⊢ ∀ x φ → x = y → ∀ x φ
3 2 axc4i-o ⊢ ∀ x φ → ∀ x x = y → ∀ x φ
4 3 a1i ⊢ ∀ z z = x → ∀ x φ → ∀ x x = y → ∀ x φ
5 biidd ⊢ ∀ z z = x → φ ↔ φ
6 5 dral1-o ⊢ ∀ z z = x → ∀ z φ ↔ ∀ x φ
7 6 imbi2d ⊢ ∀ z z = x → x = y → ∀ z φ ↔ x = y → ∀ x φ
8 7 dral2-o ⊢ ∀ z z = x → ∀ x x = y → ∀ z φ ↔ ∀ x x = y → ∀ x φ
9 4 6 8 3imtr4d ⊢ ∀ z z = x → ∀ z φ → ∀ x x = y → ∀ z φ
10 9 aecoms-o ⊢ ∀ x x = z → ∀ z φ → ∀ x x = y → ∀ z φ
11 10 a1d ⊢ ∀ x x = z → x = y → ∀ z φ → ∀ x x = y → ∀ z φ
12 11 a1d ⊢ ∀ x x = z → ¬ ∀ x x = y → x = y → ∀ z φ → ∀ x x = y → ∀ z φ
13 simplr ⊢ ¬ ∀ x x = z ∧ ¬ ∀ x x = y ∧ x = y → ¬ ∀ x x = y
14 dveeq1-o ⊢ ¬ ∀ z z = x → x = y → ∀ z x = y
15 14 naecoms-o ⊢ ¬ ∀ x x = z → x = y → ∀ z x = y
16 15 imp ⊢ ¬ ∀ x x = z ∧ x = y → ∀ z x = y
17 16 adantlr ⊢ ¬ ∀ x x = z ∧ ¬ ∀ x x = y ∧ x = y → ∀ z x = y
18 hbnae-o ⊢ ¬ ∀ x x = y → ∀ z ¬ ∀ x x = y
19 hba1-o ⊢ ∀ z x = y → ∀ z ∀ z x = y
20 18 19 hban ⊢ ¬ ∀ x x = y ∧ ∀ z x = y → ∀ z ¬ ∀ x x = y ∧ ∀ z x = y
21 ax-c5 ⊢ ∀ z x = y → x = y
22 1 imp ⊢ ¬ ∀ x x = y ∧ x = y → φ → ∀ x x = y → φ
23 21 22 sylan2 ⊢ ¬ ∀ x x = y ∧ ∀ z x = y → φ → ∀ x x = y → φ
24 20 23 alimdh ⊢ ¬ ∀ x x = y ∧ ∀ z x = y → ∀ z φ → ∀ z ∀ x x = y → φ
25 13 17 24 syl2anc ⊢ ¬ ∀ x x = z ∧ ¬ ∀ x x = y ∧ x = y → ∀ z φ → ∀ z ∀ x x = y → φ
26 ax-11 ⊢ ∀ z ∀ x x = y → φ → ∀ x ∀ z x = y → φ
27 hbnae-o ⊢ ¬ ∀ x x = z → ∀ x ¬ ∀ x x = z
28 hbnae-o ⊢ ¬ ∀ x x = z → ∀ z ¬ ∀ x x = z
29 28 15 nf5dh ⊢ ¬ ∀ x x = z → Ⅎ z x = y
30 19.21t ⊢ Ⅎ z x = y → ∀ z x = y → φ ↔ x = y → ∀ z φ
31 29 30 syl ⊢ ¬ ∀ x x = z → ∀ z x = y → φ ↔ x = y → ∀ z φ
32 27 31 albidh ⊢ ¬ ∀ x x = z → ∀ x ∀ z x = y → φ ↔ ∀ x x = y → ∀ z φ
33 26 32 imbitrid ⊢ ¬ ∀ x x = z → ∀ z ∀ x x = y → φ → ∀ x x = y → ∀ z φ
34 33 ad2antrr ⊢ ¬ ∀ x x = z ∧ ¬ ∀ x x = y ∧ x = y → ∀ z ∀ x x = y → φ → ∀ x x = y → ∀ z φ
35 25 34 syld ⊢ ¬ ∀ x x = z ∧ ¬ ∀ x x = y ∧ x = y → ∀ z φ → ∀ x x = y → ∀ z φ
36 35 exp31 ⊢ ¬ ∀ x x = z → ¬ ∀ x x = y → x = y → ∀ z φ → ∀ x x = y → ∀ z φ
37 12 36 pm2.61i ⊢ ¬ ∀ x x = y → x = y → ∀ z φ → ∀ x x = y → ∀ z φ