Metamath Proof Explorer


Theorem axi2m1

Description: i-squared equals -1 (expressed as i-squared plus 1 is 0). Axiom 12 of 22 for real and complex numbers, derived from ZF set theory. This construction-dependent theorem should not be referenced directly; instead, use ax-i2m1 . (Contributed by NM, 5-May-1996) (New usage is discouraged.)

Ref Expression
Assertion axi2m1 ⊢ i ⁢ i + 1 = 0

Proof

Step Hyp Ref Expression
1 0r ⊢ 0 𝑹 ∈ 𝑹
2 1sr ⊢ 1 𝑹 ∈ 𝑹
3 mulcnsr ⊢ 0 𝑹 ∈ 𝑹 ∧ 1 𝑹 ∈ 𝑹 ∧ 0 𝑹 ∈ 𝑹 ∧ 1 𝑹 ∈ 𝑹 → 0 𝑹 1 𝑹 ⁢ 0 𝑹 1 𝑹 = 0 𝑹 ⋅ 𝑹 0 𝑹 + 𝑹 -1 𝑹 ⋅ 𝑹 1 𝑹 ⋅ 𝑹 1 𝑹 1 𝑹 ⋅ 𝑹 0 𝑹 + 𝑹 0 𝑹 ⋅ 𝑹 1 𝑹
4 1 2 1 2 3 mp4an ⊢ 0 𝑹 1 𝑹 ⁢ 0 𝑹 1 𝑹 = 0 𝑹 ⋅ 𝑹 0 𝑹 + 𝑹 -1 𝑹 ⋅ 𝑹 1 𝑹 ⋅ 𝑹 1 𝑹 1 𝑹 ⋅ 𝑹 0 𝑹 + 𝑹 0 𝑹 ⋅ 𝑹 1 𝑹
5 00sr ⊢ 0 𝑹 ∈ 𝑹 → 0 𝑹 ⋅ 𝑹 0 𝑹 = 0 𝑹
6 1 5 ax-mp ⊢ 0 𝑹 ⋅ 𝑹 0 𝑹 = 0 𝑹
7 1idsr ⊢ 1 𝑹 ∈ 𝑹 → 1 𝑹 ⋅ 𝑹 1 𝑹 = 1 𝑹
8 2 7 ax-mp ⊢ 1 𝑹 ⋅ 𝑹 1 𝑹 = 1 𝑹
9 8 oveq2i ⊢ -1 𝑹 ⋅ 𝑹 1 𝑹 ⋅ 𝑹 1 𝑹 = -1 𝑹 ⋅ 𝑹 1 𝑹
10 m1r ⊢ -1 𝑹 ∈ 𝑹
11 1idsr ⊢ -1 𝑹 ∈ 𝑹 → -1 𝑹 ⋅ 𝑹 1 𝑹 = -1 𝑹
12 10 11 ax-mp ⊢ -1 𝑹 ⋅ 𝑹 1 𝑹 = -1 𝑹
13 9 12 eqtri ⊢ -1 𝑹 ⋅ 𝑹 1 𝑹 ⋅ 𝑹 1 𝑹 = -1 𝑹
14 6 13 oveq12i ⊢ 0 𝑹 ⋅ 𝑹 0 𝑹 + 𝑹 -1 𝑹 ⋅ 𝑹 1 𝑹 ⋅ 𝑹 1 𝑹 = 0 𝑹 + 𝑹 -1 𝑹
15 addcomsr ⊢ 0 𝑹 + 𝑹 -1 𝑹 = -1 𝑹 + 𝑹 0 𝑹
16 0idsr ⊢ -1 𝑹 ∈ 𝑹 → -1 𝑹 + 𝑹 0 𝑹 = -1 𝑹
17 10 16 ax-mp ⊢ -1 𝑹 + 𝑹 0 𝑹 = -1 𝑹
18 14 15 17 3eqtri ⊢ 0 𝑹 ⋅ 𝑹 0 𝑹 + 𝑹 -1 𝑹 ⋅ 𝑹 1 𝑹 ⋅ 𝑹 1 𝑹 = -1 𝑹
19 00sr ⊢ 1 𝑹 ∈ 𝑹 → 1 𝑹 ⋅ 𝑹 0 𝑹 = 0 𝑹
20 2 19 ax-mp ⊢ 1 𝑹 ⋅ 𝑹 0 𝑹 = 0 𝑹
21 1idsr ⊢ 0 𝑹 ∈ 𝑹 → 0 𝑹 ⋅ 𝑹 1 𝑹 = 0 𝑹
22 1 21 ax-mp ⊢ 0 𝑹 ⋅ 𝑹 1 𝑹 = 0 𝑹
23 20 22 oveq12i ⊢ 1 𝑹 ⋅ 𝑹 0 𝑹 + 𝑹 0 𝑹 ⋅ 𝑹 1 𝑹 = 0 𝑹 + 𝑹 0 𝑹
24 0idsr ⊢ 0 𝑹 ∈ 𝑹 → 0 𝑹 + 𝑹 0 𝑹 = 0 𝑹
25 1 24 ax-mp ⊢ 0 𝑹 + 𝑹 0 𝑹 = 0 𝑹
26 23 25 eqtri ⊢ 1 𝑹 ⋅ 𝑹 0 𝑹 + 𝑹 0 𝑹 ⋅ 𝑹 1 𝑹 = 0 𝑹
27 18 26 opeq12i ⊢ 0 𝑹 ⋅ 𝑹 0 𝑹 + 𝑹 -1 𝑹 ⋅ 𝑹 1 𝑹 ⋅ 𝑹 1 𝑹 1 𝑹 ⋅ 𝑹 0 𝑹 + 𝑹 0 𝑹 ⋅ 𝑹 1 𝑹 = -1 𝑹 0 𝑹
28 4 27 eqtri ⊢ 0 𝑹 1 𝑹 ⁢ 0 𝑹 1 𝑹 = -1 𝑹 0 𝑹
29 28 oveq1i ⊢ 0 𝑹 1 𝑹 ⁢ 0 𝑹 1 𝑹 + 1 𝑹 0 𝑹 = -1 𝑹 0 𝑹 + 1 𝑹 0 𝑹
30 addresr ⊢ -1 𝑹 ∈ 𝑹 ∧ 1 𝑹 ∈ 𝑹 → -1 𝑹 0 𝑹 + 1 𝑹 0 𝑹 = -1 𝑹 + 𝑹 1 𝑹 0 𝑹
31 10 2 30 mp2an ⊢ -1 𝑹 0 𝑹 + 1 𝑹 0 𝑹 = -1 𝑹 + 𝑹 1 𝑹 0 𝑹
32 m1p1sr ⊢ -1 𝑹 + 𝑹 1 𝑹 = 0 𝑹
33 32 opeq1i ⊢ -1 𝑹 + 𝑹 1 𝑹 0 𝑹 = 0 𝑹 0 𝑹
34 29 31 33 3eqtri ⊢ 0 𝑹 1 𝑹 ⁢ 0 𝑹 1 𝑹 + 1 𝑹 0 𝑹 = 0 𝑹 0 𝑹
35 df-i ⊢ i = 0 𝑹 1 𝑹
36 35 35 oveq12i ⊢ i ⁢ i = 0 𝑹 1 𝑹 ⁢ 0 𝑹 1 𝑹
37 df-1 ⊢ 1 = 1 𝑹 0 𝑹
38 36 37 oveq12i ⊢ i ⁢ i + 1 = 0 𝑹 1 𝑹 ⁢ 0 𝑹 1 𝑹 + 1 𝑹 0 𝑹
39 df-0 ⊢ 0 = 0 𝑹 0 𝑹
40 34 38 39 3eqtr4i ⊢ i ⁢ i + 1 = 0