Metamath Proof Explorer


Theorem bianim

Description: Exchanging conjunction in a biconditional. (Contributed by Peter Mazsa, 31-Jul-2023)

Ref Expression
Hypotheses bianim.1 ⊢ φ ↔ ψ ∧ χ
bianim.2 ⊢ χ → ψ ↔ θ
Assertion bianim ⊢ φ ↔ θ ∧ χ

Proof

Step Hyp Ref Expression
1 bianim.1 ⊢ φ ↔ ψ ∧ χ
2 bianim.2 ⊢ χ → ψ ↔ θ
3 2 pm5.32ri ⊢ ψ ∧ χ ↔ θ ∧ χ
4 1 3 bitri ⊢ φ ↔ θ ∧ χ