Metamath Proof Explorer


Theorem bitsinv

Description: The inverse of the bits function. (Contributed by Mario Carneiro, 8-Sep-2016)

Ref Expression
Hypothesis bitsinv.k ⊢ K = bits ↾ ℕ 0 -1
Assertion bitsinv ⊢ A ∈ 𝒫 ℕ 0 ∩ Fin → K ⁡ A = ∑ k ∈ A 2 k

Proof

Step Hyp Ref Expression
1 bitsinv.k ⊢ K = bits ↾ ℕ 0 -1
2 sumeq1 ⊢ x = A → ∑ k ∈ x 2 k = ∑ k ∈ A 2 k
3 bitsf1ocnv ⊢ bits ↾ ℕ 0 : ℕ 0 ⟶ 1-1 onto 𝒫 ℕ 0 ∩ Fin ∧ bits ↾ ℕ 0 -1 = x ∈ 𝒫 ℕ 0 ∩ Fin ⟼ ∑ k ∈ x 2 k
4 3 simpri ⊢ bits ↾ ℕ 0 -1 = x ∈ 𝒫 ℕ 0 ∩ Fin ⟼ ∑ k ∈ x 2 k
5 1 4 eqtri ⊢ K = x ∈ 𝒫 ℕ 0 ∩ Fin ⟼ ∑ k ∈ x 2 k
6 sumex ⊢ ∑ k ∈ A 2 k ∈ V
7 2 5 6 fvmpt ⊢ A ∈ 𝒫 ℕ 0 ∩ Fin → K ⁡ A = ∑ k ∈ A 2 k