Metamath Proof Explorer


Theorem bj-gabeqd

Description: Equality of generalized class abstractions. Deduction form. (Contributed by BJ, 4-Oct-2024)

Ref Expression
Hypotheses bj-gabeqd.nf ⊢ φ → ∀ x φ
bj-gabeqd.c ⊢ φ → A = B
bj-gabeqd.f ⊢ φ → ψ ↔ χ
Assertion bj-gabeqd ⊢ φ → A | x | ψ = B | x | χ

Proof

Step Hyp Ref Expression
1 bj-gabeqd.nf ⊢ φ → ∀ x φ
2 bj-gabeqd.c ⊢ φ → A = B
3 bj-gabeqd.f ⊢ φ → ψ ↔ χ
4 3 biimpd ⊢ φ → ψ → χ
5 1 2 4 bj-gabssd ⊢ φ → A | x | ψ ⊆ B | x | χ
6 2 eqcomd ⊢ φ → B = A
7 3 biimprd ⊢ φ → χ → ψ
8 1 6 7 bj-gabssd ⊢ φ → B | x | χ ⊆ A | x | ψ
9 5 8 eqssd ⊢ φ → A | x | ψ = B | x | χ