Metamath Proof Explorer


Theorem bj-snexg

Description: A singleton built on a set is a set. Contrary to bj-snex , this proof is intuitionistically valid and does not require ax-nul . (Contributed by NM, 7-Aug-1994) Extract it from snex and prove it from ax-bj-sn . (Revised by BJ, 12-Jan-2025) (Proof modification is discouraged.)

Ref Expression
Assertion bj-snexg ⊢ A ∈ V → A ∈ V

Proof

Step Hyp Ref Expression
1 sneq ⊢ x = A → x = A
2 ax-bj-sn ⊢ ∀ x ∃ y ∀ z z ∈ y ↔ z = x
3 2 spi ⊢ ∃ y ∀ z z ∈ y ↔ z = x
4 bj-axsn ⊢ x ∈ V ↔ ∃ y ∀ z z ∈ y ↔ z = x
5 3 4 mpbir ⊢ x ∈ V
6 1 5 eqeltrrdi ⊢ x = A → A ∈ V
7 6 vtocleg ⊢ A ∈ V → A ∈ V