Metamath Proof Explorer


Theorem btwnhl2

Description: Deduce half-line from betweenness. (Contributed by Thierry Arnoux, 4-Mar-2020)

Ref Expression
Hypotheses ishlg.p ⊢ P = Base G
ishlg.i ⊢ I = Itv ⁡ G
ishlg.k ⊢ K = hl 𝒢 ⁡ G
ishlg.a ⊢ φ → A ∈ P
ishlg.b ⊢ φ → B ∈ P
ishlg.c ⊢ φ → C ∈ P
hlln.1 ⊢ φ → G ∈ 𝒢 Tarski
hltr.d ⊢ φ → D ∈ P
btwnhl1.1 ⊢ φ → C ∈ A I B
btwnhl1.2 ⊢ φ → A ≠ B
btwnhl2.3 ⊢ φ → C ≠ B
Assertion btwnhl2 ⊢ φ → C K ⁡ B A

Proof

Step Hyp Ref Expression
1 ishlg.p ⊢ P = Base G
2 ishlg.i ⊢ I = Itv ⁡ G
3 ishlg.k ⊢ K = hl 𝒢 ⁡ G
4 ishlg.a ⊢ φ → A ∈ P
5 ishlg.b ⊢ φ → B ∈ P
6 ishlg.c ⊢ φ → C ∈ P
7 hlln.1 ⊢ φ → G ∈ 𝒢 Tarski
8 hltr.d ⊢ φ → D ∈ P
9 btwnhl1.1 ⊢ φ → C ∈ A I B
10 btwnhl1.2 ⊢ φ → A ≠ B
11 btwnhl2.3 ⊢ φ → C ≠ B
12 eqid ⊢ dist ⁡ G = dist ⁡ G
13 1 12 2 7 4 6 5 9 tgbtwncom ⊢ φ → C ∈ B I A
14 13 orcd ⊢ φ → C ∈ B I A ∨ A ∈ B I C
15 1 2 3 6 4 5 7 ishlg ⊢ φ → C K ⁡ B A ↔ C ≠ B ∧ A ≠ B ∧ C ∈ B I A ∨ A ∈ B I C
16 11 10 14 15 mpbir3and ⊢ φ → C K ⁡ B A