Metamath Proof Explorer


Theorem cdlemk30

Description: Part of proof of Lemma K of Crawley p. 118. TODO: fix comment. Part of attempt to simplify hypotheses. (Contributed by NM, 17-Jul-2013)

Ref Expression
Hypotheses cdlemk3.b ⊢ B = Base K
cdlemk3.l ⊢ ≤ ˙ = ≤ K
cdlemk3.j ⊢ ∨ ˙ = join ⁡ K
cdlemk3.m ⊢ ∧ ˙ = meet ⁡ K
cdlemk3.a ⊢ A = Atoms ⁡ K
cdlemk3.h ⊢ H = LHyp ⁡ K
cdlemk3.t ⊢ T = LTrn ⁡ K ⁡ W
cdlemk3.r ⊢ R = trL ⁡ K ⁡ W
cdlemk3.s ⊢ S = f ∈ T ⟼ ι i ∈ T | i ⁡ P = P ∨ ˙ R ⁡ f ∧ ˙ N ⁡ P ∨ ˙ R ⁡ f ∘ F -1
Assertion cdlemk30 ⊢ K ∈ HL ∧ W ∈ H ∧ R ⁡ F = R ⁡ N ∧ F ∈ T ∧ b ∈ T ∧ N ∈ T ∧ R ⁡ b ≠ R ⁡ F ∧ F ≠ I ↾ B ∧ b ≠ I ↾ B ∧ P ∈ A ∧ ¬ P ≤ ˙ W → S ⁡ b ⁡ P = P ∨ ˙ R ⁡ b ∧ ˙ N ⁡ P ∨ ˙ R ⁡ b ∘ F -1

Proof

Step Hyp Ref Expression
1 cdlemk3.b ⊢ B = Base K
2 cdlemk3.l ⊢ ≤ ˙ = ≤ K
3 cdlemk3.j ⊢ ∨ ˙ = join ⁡ K
4 cdlemk3.m ⊢ ∧ ˙ = meet ⁡ K
5 cdlemk3.a ⊢ A = Atoms ⁡ K
6 cdlemk3.h ⊢ H = LHyp ⁡ K
7 cdlemk3.t ⊢ T = LTrn ⁡ K ⁡ W
8 cdlemk3.r ⊢ R = trL ⁡ K ⁡ W
9 cdlemk3.s ⊢ S = f ∈ T ⟼ ι i ∈ T | i ⁡ P = P ∨ ˙ R ⁡ f ∧ ˙ N ⁡ P ∨ ˙ R ⁡ f ∘ F -1
10 simp1l ⊢ K ∈ HL ∧ W ∈ H ∧ R ⁡ F = R ⁡ N ∧ F ∈ T ∧ b ∈ T ∧ N ∈ T ∧ R ⁡ b ≠ R ⁡ F ∧ F ≠ I ↾ B ∧ b ≠ I ↾ B ∧ P ∈ A ∧ ¬ P ≤ ˙ W → K ∈ HL ∧ W ∈ H
11 simp21 ⊢ K ∈ HL ∧ W ∈ H ∧ R ⁡ F = R ⁡ N ∧ F ∈ T ∧ b ∈ T ∧ N ∈ T ∧ R ⁡ b ≠ R ⁡ F ∧ F ≠ I ↾ B ∧ b ≠ I ↾ B ∧ P ∈ A ∧ ¬ P ≤ ˙ W → F ∈ T
12 simp22 ⊢ K ∈ HL ∧ W ∈ H ∧ R ⁡ F = R ⁡ N ∧ F ∈ T ∧ b ∈ T ∧ N ∈ T ∧ R ⁡ b ≠ R ⁡ F ∧ F ≠ I ↾ B ∧ b ≠ I ↾ B ∧ P ∈ A ∧ ¬ P ≤ ˙ W → b ∈ T
13 simp23 ⊢ K ∈ HL ∧ W ∈ H ∧ R ⁡ F = R ⁡ N ∧ F ∈ T ∧ b ∈ T ∧ N ∈ T ∧ R ⁡ b ≠ R ⁡ F ∧ F ≠ I ↾ B ∧ b ≠ I ↾ B ∧ P ∈ A ∧ ¬ P ≤ ˙ W → N ∈ T
14 simp33 ⊢ K ∈ HL ∧ W ∈ H ∧ R ⁡ F = R ⁡ N ∧ F ∈ T ∧ b ∈ T ∧ N ∈ T ∧ R ⁡ b ≠ R ⁡ F ∧ F ≠ I ↾ B ∧ b ≠ I ↾ B ∧ P ∈ A ∧ ¬ P ≤ ˙ W → P ∈ A ∧ ¬ P ≤ ˙ W
15 simp1r ⊢ K ∈ HL ∧ W ∈ H ∧ R ⁡ F = R ⁡ N ∧ F ∈ T ∧ b ∈ T ∧ N ∈ T ∧ R ⁡ b ≠ R ⁡ F ∧ F ≠ I ↾ B ∧ b ≠ I ↾ B ∧ P ∈ A ∧ ¬ P ≤ ˙ W → R ⁡ F = R ⁡ N
16 simp32l ⊢ K ∈ HL ∧ W ∈ H ∧ R ⁡ F = R ⁡ N ∧ F ∈ T ∧ b ∈ T ∧ N ∈ T ∧ R ⁡ b ≠ R ⁡ F ∧ F ≠ I ↾ B ∧ b ≠ I ↾ B ∧ P ∈ A ∧ ¬ P ≤ ˙ W → F ≠ I ↾ B
17 simp32r ⊢ K ∈ HL ∧ W ∈ H ∧ R ⁡ F = R ⁡ N ∧ F ∈ T ∧ b ∈ T ∧ N ∈ T ∧ R ⁡ b ≠ R ⁡ F ∧ F ≠ I ↾ B ∧ b ≠ I ↾ B ∧ P ∈ A ∧ ¬ P ≤ ˙ W → b ≠ I ↾ B
18 simp31 ⊢ K ∈ HL ∧ W ∈ H ∧ R ⁡ F = R ⁡ N ∧ F ∈ T ∧ b ∈ T ∧ N ∈ T ∧ R ⁡ b ≠ R ⁡ F ∧ F ≠ I ↾ B ∧ b ≠ I ↾ B ∧ P ∈ A ∧ ¬ P ≤ ˙ W → R ⁡ b ≠ R ⁡ F
19 1 2 3 5 6 7 8 4 9 cdlemksv2 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ b ∈ T ∧ N ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ R ⁡ F = R ⁡ N ∧ F ≠ I ↾ B ∧ b ≠ I ↾ B ∧ R ⁡ b ≠ R ⁡ F → S ⁡ b ⁡ P = P ∨ ˙ R ⁡ b ∧ ˙ N ⁡ P ∨ ˙ R ⁡ b ∘ F -1
20 10 11 12 13 14 15 16 17 18 19 syl333anc ⊢ K ∈ HL ∧ W ∈ H ∧ R ⁡ F = R ⁡ N ∧ F ∈ T ∧ b ∈ T ∧ N ∈ T ∧ R ⁡ b ≠ R ⁡ F ∧ F ≠ I ↾ B ∧ b ≠ I ↾ B ∧ P ∈ A ∧ ¬ P ≤ ˙ W → S ⁡ b ⁡ P = P ∨ ˙ R ⁡ b ∧ ˙ N ⁡ P ∨ ˙ R ⁡ b ∘ F -1