Metamath Proof Explorer


Theorem chscl

Description: The subspace sum of two closed orthogonal spaces is closed. (Contributed by NM, 19-Oct-1999) (Proof shortened by Mario Carneiro, 19-May-2014) (New usage is discouraged.)

Ref Expression
Hypotheses chscl.1 ⊢ φ → A ∈ C ℋ
chscl.2 ⊢ φ → B ∈ C ℋ
chscl.3 ⊢ φ → B ⊆ ⊥ ⁡ A
Assertion chscl ⊢ φ → A + ℋ B ∈ C ℋ

Proof

Step Hyp Ref Expression
1 chscl.1 ⊢ φ → A ∈ C ℋ
2 chscl.2 ⊢ φ → B ∈ C ℋ
3 chscl.3 ⊢ φ → B ⊆ ⊥ ⁡ A
4 chsh ⊢ A ∈ C ℋ → A ∈ S ℋ
5 1 4 syl ⊢ φ → A ∈ S ℋ
6 chsh ⊢ B ∈ C ℋ → B ∈ S ℋ
7 2 6 syl ⊢ φ → B ∈ S ℋ
8 shscl ⊢ A ∈ S ℋ ∧ B ∈ S ℋ → A + ℋ B ∈ S ℋ
9 5 7 8 syl2anc ⊢ φ → A + ℋ B ∈ S ℋ
10 1 adantr ⊢ φ ∧ f : ℕ ⟶ A + ℋ B ∧ f ⇝v z → A ∈ C ℋ
11 2 adantr ⊢ φ ∧ f : ℕ ⟶ A + ℋ B ∧ f ⇝v z → B ∈ C ℋ
12 3 adantr ⊢ φ ∧ f : ℕ ⟶ A + ℋ B ∧ f ⇝v z → B ⊆ ⊥ ⁡ A
13 simprl ⊢ φ ∧ f : ℕ ⟶ A + ℋ B ∧ f ⇝v z → f : ℕ ⟶ A + ℋ B
14 simprr ⊢ φ ∧ f : ℕ ⟶ A + ℋ B ∧ f ⇝v z → f ⇝v z
15 eqid ⊢ x ∈ ℕ ⟼ proj ℎ ⁡ A ⁡ f ⁡ x = x ∈ ℕ ⟼ proj ℎ ⁡ A ⁡ f ⁡ x
16 eqid ⊢ x ∈ ℕ ⟼ proj ℎ ⁡ B ⁡ f ⁡ x = x ∈ ℕ ⟼ proj ℎ ⁡ B ⁡ f ⁡ x
17 10 11 12 13 14 15 16 chscllem4 ⊢ φ ∧ f : ℕ ⟶ A + ℋ B ∧ f ⇝v z → z ∈ A + ℋ B
18 17 ex ⊢ φ → f : ℕ ⟶ A + ℋ B ∧ f ⇝v z → z ∈ A + ℋ B
19 18 alrimivv ⊢ φ → ∀ f ∀ z f : ℕ ⟶ A + ℋ B ∧ f ⇝v z → z ∈ A + ℋ B
20 isch2 ⊢ A + ℋ B ∈ C ℋ ↔ A + ℋ B ∈ S ℋ ∧ ∀ f ∀ z f : ℕ ⟶ A + ℋ B ∧ f ⇝v z → z ∈ A + ℋ B
21 9 19 20 sylanbrc ⊢ φ → A + ℋ B ∈ C ℋ