Metamath Proof Explorer


Theorem cnegex2

Description: Existence of a left inverse for addition. (Contributed by Scott Fenton, 3-Jan-2013)

Ref Expression
Assertion cnegex2 ⊢ A ∈ ℂ → ∃ x ∈ ℂ x + A = 0

Proof

Step Hyp Ref Expression
1 ax-icn ⊢ i ∈ ℂ
2 1 1 mulcli ⊢ i ⁢ i ∈ ℂ
3 mulcl ⊢ i ⁢ i ∈ ℂ ∧ A ∈ ℂ → i ⁢ i ⁢ A ∈ ℂ
4 2 3 mpan ⊢ A ∈ ℂ → i ⁢ i ⁢ A ∈ ℂ
5 mullid ⊢ A ∈ ℂ → 1 ⁢ A = A
6 5 oveq2d ⊢ A ∈ ℂ → i ⁢ i ⁢ A + 1 ⁢ A = i ⁢ i ⁢ A + A
7 ax-i2m1 ⊢ i ⁢ i + 1 = 0
8 7 oveq1i ⊢ i ⁢ i + 1 ⁢ A = 0 ⋅ A
9 ax-1cn ⊢ 1 ∈ ℂ
10 adddir ⊢ i ⁢ i ∈ ℂ ∧ 1 ∈ ℂ ∧ A ∈ ℂ → i ⁢ i + 1 ⁢ A = i ⁢ i ⁢ A + 1 ⁢ A
11 2 9 10 mp3an12 ⊢ A ∈ ℂ → i ⁢ i + 1 ⁢ A = i ⁢ i ⁢ A + 1 ⁢ A
12 mul02 ⊢ A ∈ ℂ → 0 ⋅ A = 0
13 8 11 12 3eqtr3a ⊢ A ∈ ℂ → i ⁢ i ⁢ A + 1 ⁢ A = 0
14 6 13 eqtr3d ⊢ A ∈ ℂ → i ⁢ i ⁢ A + A = 0
15 oveq1 ⊢ x = i ⁢ i ⁢ A → x + A = i ⁢ i ⁢ A + A
16 15 eqeq1d ⊢ x = i ⁢ i ⁢ A → x + A = 0 ↔ i ⁢ i ⁢ A + A = 0
17 16 rspcev ⊢ i ⁢ i ⁢ A ∈ ℂ ∧ i ⁢ i ⁢ A + A = 0 → ∃ x ∈ ℂ x + A = 0
18 4 14 17 syl2anc ⊢ A ∈ ℂ → ∃ x ∈ ℂ x + A = 0