Metamath Proof Explorer


Theorem coa2

Description: The morphism part of arrow composition. (Contributed by Mario Carneiro, 11-Jan-2017)

Ref Expression
Hypotheses homdmcoa.o ⊢ · ˙ = comp a ⁡ C
homdmcoa.h ⊢ H = Hom a ⁡ C
homdmcoa.f ⊢ φ → F ∈ X H Y
homdmcoa.g ⊢ φ → G ∈ Y H Z
coaval.x ⊢ ∙ ˙ = comp ⁡ C
Assertion coa2 ⊢ φ → 2 nd ⁡ G · ˙ F = 2 nd ⁡ G X Y ∙ ˙ Z 2 nd ⁡ F

Proof

Step Hyp Ref Expression
1 homdmcoa.o ⊢ · ˙ = comp a ⁡ C
2 homdmcoa.h ⊢ H = Hom a ⁡ C
3 homdmcoa.f ⊢ φ → F ∈ X H Y
4 homdmcoa.g ⊢ φ → G ∈ Y H Z
5 coaval.x ⊢ ∙ ˙ = comp ⁡ C
6 1 2 3 4 5 coaval ⊢ φ → G · ˙ F = X Z 2 nd ⁡ G X Y ∙ ˙ Z 2 nd ⁡ F
7 6 fveq2d ⊢ φ → 2 nd ⁡ G · ˙ F = 2 nd ⁡ X Z 2 nd ⁡ G X Y ∙ ˙ Z 2 nd ⁡ F
8 ovex ⊢ 2 nd ⁡ G X Y ∙ ˙ Z 2 nd ⁡ F ∈ V
9 ot3rdg ⊢ 2 nd ⁡ G X Y ∙ ˙ Z 2 nd ⁡ F ∈ V → 2 nd ⁡ X Z 2 nd ⁡ G X Y ∙ ˙ Z 2 nd ⁡ F = 2 nd ⁡ G X Y ∙ ˙ Z 2 nd ⁡ F
10 8 9 ax-mp ⊢ 2 nd ⁡ X Z 2 nd ⁡ G X Y ∙ ˙ Z 2 nd ⁡ F = 2 nd ⁡ G X Y ∙ ˙ Z 2 nd ⁡ F
11 7 10 eqtrdi ⊢ φ → 2 nd ⁡ G · ˙ F = 2 nd ⁡ G X Y ∙ ˙ Z 2 nd ⁡ F