Metamath Proof Explorer


Theorem coahom

Description: The composition of two composable arrows is an arrow. (Contributed by Mario Carneiro, 11-Jan-2017)

Ref Expression
Hypotheses homdmcoa.o ⊢ · ˙ = comp a ⁡ C
homdmcoa.h ⊢ H = Hom a ⁡ C
homdmcoa.f ⊢ φ → F ∈ X H Y
homdmcoa.g ⊢ φ → G ∈ Y H Z
Assertion coahom ⊢ φ → G · ˙ F ∈ X H Z

Proof

Step Hyp Ref Expression
1 homdmcoa.o ⊢ · ˙ = comp a ⁡ C
2 homdmcoa.h ⊢ H = Hom a ⁡ C
3 homdmcoa.f ⊢ φ → F ∈ X H Y
4 homdmcoa.g ⊢ φ → G ∈ Y H Z
5 eqid ⊢ comp ⁡ C = comp ⁡ C
6 1 2 3 4 5 coaval ⊢ φ → G · ˙ F = X Z 2 nd ⁡ G X Y comp ⁡ C Z 2 nd ⁡ F
7 eqid ⊢ Base C = Base C
8 2 homarcl ⊢ F ∈ X H Y → C ∈ Cat
9 3 8 syl ⊢ φ → C ∈ Cat
10 eqid ⊢ Hom ⁡ C = Hom ⁡ C
11 2 7 homarcl2 ⊢ F ∈ X H Y → X ∈ Base C ∧ Y ∈ Base C
12 3 11 syl ⊢ φ → X ∈ Base C ∧ Y ∈ Base C
13 12 simpld ⊢ φ → X ∈ Base C
14 2 7 homarcl2 ⊢ G ∈ Y H Z → Y ∈ Base C ∧ Z ∈ Base C
15 4 14 syl ⊢ φ → Y ∈ Base C ∧ Z ∈ Base C
16 15 simprd ⊢ φ → Z ∈ Base C
17 12 simprd ⊢ φ → Y ∈ Base C
18 2 10 homahom ⊢ F ∈ X H Y → 2 nd ⁡ F ∈ X Hom ⁡ C Y
19 3 18 syl ⊢ φ → 2 nd ⁡ F ∈ X Hom ⁡ C Y
20 2 10 homahom ⊢ G ∈ Y H Z → 2 nd ⁡ G ∈ Y Hom ⁡ C Z
21 4 20 syl ⊢ φ → 2 nd ⁡ G ∈ Y Hom ⁡ C Z
22 7 10 5 9 13 17 16 19 21 catcocl ⊢ φ → 2 nd ⁡ G X Y comp ⁡ C Z 2 nd ⁡ F ∈ X Hom ⁡ C Z
23 2 7 9 10 13 16 22 elhomai2 ⊢ φ → X Z 2 nd ⁡ G X Y comp ⁡ C Z 2 nd ⁡ F ∈ X H Z
24 6 23 eqeltrd ⊢ φ → G · ˙ F ∈ X H Z