Metamath Proof Explorer


Theorem conrel1d

Description: Deduction about composition with a class with no relational content. (Contributed by RP, 24-Dec-2019)

Ref Expression
Hypothesis conrel1d.a ⊢ φ → A -1 = ∅
Assertion conrel1d ⊢ φ → A ∘ B = ∅

Proof

Step Hyp Ref Expression
1 conrel1d.a ⊢ φ → A -1 = ∅
2 incom ⊢ dom ⁡ A ∩ ran ⁡ B = ran ⁡ B ∩ dom ⁡ A
3 dfdm4 ⊢ dom ⁡ A = ran ⁡ A -1
4 1 rneqd ⊢ φ → ran ⁡ A -1 = ran ⁡ ∅
5 rn0 ⊢ ran ⁡ ∅ = ∅
6 4 5 eqtrdi ⊢ φ → ran ⁡ A -1 = ∅
7 3 6 eqtrid ⊢ φ → dom ⁡ A = ∅
8 ineq2 ⊢ dom ⁡ A = ∅ → ran ⁡ B ∩ dom ⁡ A = ran ⁡ B ∩ ∅
9 in0 ⊢ ran ⁡ B ∩ ∅ = ∅
10 8 9 eqtrdi ⊢ dom ⁡ A = ∅ → ran ⁡ B ∩ dom ⁡ A = ∅
11 7 10 syl ⊢ φ → ran ⁡ B ∩ dom ⁡ A = ∅
12 2 11 eqtrid ⊢ φ → dom ⁡ A ∩ ran ⁡ B = ∅
13 12 coemptyd ⊢ φ → A ∘ B = ∅