Metamath Proof Explorer


Theorem conrel2d

Description: Deduction about composition with a class with no relational content. (Contributed by RP, 24-Dec-2019)

Ref Expression
Hypothesis conrel1d.a ⊢ φ → A -1 = ∅
Assertion conrel2d ⊢ φ → B ∘ A = ∅

Proof

Step Hyp Ref Expression
1 conrel1d.a ⊢ φ → A -1 = ∅
2 df-rn ⊢ ran ⁡ A = dom ⁡ A -1
3 2 ineq2i ⊢ dom ⁡ B ∩ ran ⁡ A = dom ⁡ B ∩ dom ⁡ A -1
4 3 a1i ⊢ φ → dom ⁡ B ∩ ran ⁡ A = dom ⁡ B ∩ dom ⁡ A -1
5 1 dmeqd ⊢ φ → dom ⁡ A -1 = dom ⁡ ∅
6 5 ineq2d ⊢ φ → dom ⁡ B ∩ dom ⁡ A -1 = dom ⁡ B ∩ dom ⁡ ∅
7 dm0 ⊢ dom ⁡ ∅ = ∅
8 7 ineq2i ⊢ dom ⁡ B ∩ dom ⁡ ∅ = dom ⁡ B ∩ ∅
9 in0 ⊢ dom ⁡ B ∩ ∅ = ∅
10 8 9 eqtri ⊢ dom ⁡ B ∩ dom ⁡ ∅ = ∅
11 10 a1i ⊢ φ → dom ⁡ B ∩ dom ⁡ ∅ = ∅
12 4 6 11 3eqtrd ⊢ φ → dom ⁡ B ∩ ran ⁡ A = ∅
13 12 coemptyd ⊢ φ → B ∘ A = ∅