Metamath Proof Explorer


Theorem crngbinom

Description: The binomial theorem for commutative rings (special case of csrgbinom ): ( A + B ) ^ N is the sum from k = 0 to N of ( N _C k ) x. ( ( A ^ k ) x. ( B ^ ( N - k ) ) . (Contributed by AV, 24-Aug-2019)

Ref Expression
Hypotheses crngbinom.s ⊢ S = Base R
crngbinom.m ⊢ × ˙ = ⋅ R
crngbinom.t ⊢ · ˙ = ⋅ R
crngbinom.a ⊢ + ˙ = + R
crngbinom.g ⊢ G = mulGrp R
crngbinom.e ⊢ × ˙ = ⋅ G
Assertion crngbinom ⊢ R ∈ CRing ∧ N ∈ ℕ 0 ∧ A ∈ S ∧ B ∈ S → N × ˙ A + ˙ B = ∑ R k = 0 N ( N k) · ˙ N − k × ˙ A × ˙ k × ˙ B

Proof

Step Hyp Ref Expression
1 crngbinom.s ⊢ S = Base R
2 crngbinom.m ⊢ × ˙ = ⋅ R
3 crngbinom.t ⊢ · ˙ = ⋅ R
4 crngbinom.a ⊢ + ˙ = + R
5 crngbinom.g ⊢ G = mulGrp R
6 crngbinom.e ⊢ × ˙ = ⋅ G
7 crngring ⊢ R ∈ CRing → R ∈ Ring
8 ringsrg ⊢ R ∈ Ring → R ∈ SRing
9 7 8 syl ⊢ R ∈ CRing → R ∈ SRing
10 9 adantr ⊢ R ∈ CRing ∧ N ∈ ℕ 0 → R ∈ SRing
11 5 crngmgp ⊢ R ∈ CRing → G ∈ CMnd
12 11 adantr ⊢ R ∈ CRing ∧ N ∈ ℕ 0 → G ∈ CMnd
13 simpr ⊢ R ∈ CRing ∧ N ∈ ℕ 0 → N ∈ ℕ 0
14 10 12 13 3jca ⊢ R ∈ CRing ∧ N ∈ ℕ 0 → R ∈ SRing ∧ G ∈ CMnd ∧ N ∈ ℕ 0
15 1 2 3 4 5 6 csrgbinom ⊢ R ∈ SRing ∧ G ∈ CMnd ∧ N ∈ ℕ 0 ∧ A ∈ S ∧ B ∈ S → N × ˙ A + ˙ B = ∑ R k = 0 N ( N k) · ˙ N − k × ˙ A × ˙ k × ˙ B
16 14 15 sylan ⊢ R ∈ CRing ∧ N ∈ ℕ 0 ∧ A ∈ S ∧ B ∈ S → N × ˙ A + ˙ B = ∑ R k = 0 N ( N k) · ˙ N − k × ˙ A × ˙ k × ˙ B