Metamath Proof Explorer


Theorem deg1vscale

Description: The degree of a scalar times a polynomial is at most the degree of the original polynomial. (Contributed by Stefan O'Rear, 26-Mar-2015)

Ref Expression
Hypotheses deg1addle.y ⊢ Y = Poly 1 ⁡ R
deg1addle.d ⊢ D = deg 1 ⁡ R
deg1addle.r ⊢ φ → R ∈ Ring
deg1vscale.b ⊢ B = Base Y
deg1vscale.k ⊢ K = Base R
deg1vscale.p ⊢ · ˙ = ⋅ Y
deg1vscale.f ⊢ φ → F ∈ K
deg1vscale.g ⊢ φ → G ∈ B
Assertion deg1vscale ⊢ φ → D ⁡ F · ˙ G ≤ D ⁡ G

Proof

Step Hyp Ref Expression
1 deg1addle.y ⊢ Y = Poly 1 ⁡ R
2 deg1addle.d ⊢ D = deg 1 ⁡ R
3 deg1addle.r ⊢ φ → R ∈ Ring
4 deg1vscale.b ⊢ B = Base Y
5 deg1vscale.k ⊢ K = Base R
6 deg1vscale.p ⊢ · ˙ = ⋅ Y
7 deg1vscale.f ⊢ φ → F ∈ K
8 deg1vscale.g ⊢ φ → G ∈ B
9 eqid ⊢ 1 𝑜 mPoly R = 1 𝑜 mPoly R
10 2 deg1fval ⊢ D = 1 𝑜 mDeg R
11 1on ⊢ 1 𝑜 ∈ On
12 11 a1i ⊢ φ → 1 𝑜 ∈ On
13 1 4 ply1bas ⊢ B = Base 1 𝑜 mPoly R
14 1 9 6 ply1vsca ⊢ · ˙ = ⋅ 1 𝑜 mPoly R
15 9 10 12 3 13 5 14 7 8 mdegvscale ⊢ φ → D ⁡ F · ˙ G ≤ D ⁡ G