Metamath Proof Explorer


Theorem difin0ss

Description: Difference, intersection, and subclass relationship. (Contributed by NM, 30-Apr-1994) (Proof shortened by Wolf Lammen, 30-Sep-2014)

Ref Expression
Assertion difin0ss ⊢ A ∖ B ∩ C = ∅ → C ⊆ A → C ⊆ B

Proof

Step Hyp Ref Expression
1 eq0 ⊢ A ∖ B ∩ C = ∅ ↔ ∀ x ¬ x ∈ A ∖ B ∩ C
2 iman ⊢ x ∈ C → x ∈ A → x ∈ B ↔ ¬ x ∈ C ∧ ¬ x ∈ A → x ∈ B
3 elin ⊢ x ∈ A ∖ B ∩ C ↔ x ∈ A ∖ B ∧ x ∈ C
4 eldif ⊢ x ∈ A ∖ B ↔ x ∈ A ∧ ¬ x ∈ B
5 4 anbi2ci ⊢ x ∈ A ∖ B ∧ x ∈ C ↔ x ∈ C ∧ x ∈ A ∧ ¬ x ∈ B
6 annim ⊢ x ∈ A ∧ ¬ x ∈ B ↔ ¬ x ∈ A → x ∈ B
7 6 anbi2i ⊢ x ∈ C ∧ x ∈ A ∧ ¬ x ∈ B ↔ x ∈ C ∧ ¬ x ∈ A → x ∈ B
8 3 5 7 3bitri ⊢ x ∈ A ∖ B ∩ C ↔ x ∈ C ∧ ¬ x ∈ A → x ∈ B
9 2 8 xchbinxr ⊢ x ∈ C → x ∈ A → x ∈ B ↔ ¬ x ∈ A ∖ B ∩ C
10 ax-2 ⊢ x ∈ C → x ∈ A → x ∈ B → x ∈ C → x ∈ A → x ∈ C → x ∈ B
11 9 10 sylbir ⊢ ¬ x ∈ A ∖ B ∩ C → x ∈ C → x ∈ A → x ∈ C → x ∈ B
12 11 al2imi ⊢ ∀ x ¬ x ∈ A ∖ B ∩ C → ∀ x x ∈ C → x ∈ A → ∀ x x ∈ C → x ∈ B
13 df-ss ⊢ C ⊆ A ↔ ∀ x x ∈ C → x ∈ A
14 df-ss ⊢ C ⊆ B ↔ ∀ x x ∈ C → x ∈ B
15 12 13 14 3imtr4g ⊢ ∀ x ¬ x ∈ A ∖ B ∩ C → C ⊆ A → C ⊆ B
16 1 15 sylbi ⊢ A ∖ B ∩ C = ∅ → C ⊆ A → C ⊆ B