Metamath Proof Explorer


Theorem dissneq

Description: Any topology that contains every single-point set is the discrete topology. (Contributed by ML, 16-Jul-2020)

Ref Expression
Hypothesis dissneq.c ⊢ C = u | ∃ x ∈ A u = x
Assertion dissneq ⊢ C ⊆ B ∧ B ∈ TopOn ⁡ A → B = 𝒫 A

Proof

Step Hyp Ref Expression
1 dissneq.c ⊢ C = u | ∃ x ∈ A u = x
2 sneq ⊢ z = x → z = x
3 2 eqeq2d ⊢ z = x → u = z ↔ u = x
4 3 cbvrexvw ⊢ ∃ z ∈ A u = z ↔ ∃ x ∈ A u = x
5 4 abbii ⊢ u | ∃ z ∈ A u = z = u | ∃ x ∈ A u = x
6 1 5 eqtr4i ⊢ C = u | ∃ z ∈ A u = z
7 6 dissneqlem ⊢ C ⊆ B ∧ B ∈ TopOn ⁡ A → B = 𝒫 A