Metamath Proof Explorer


Theorem dvreq1

Description: Equality in terms of ratio equal to ring unity. ( diveq1 analog.) (Contributed by Mario Carneiro, 28-Apr-2016)

Ref Expression
Hypotheses dvreq1.b ⊢ B = Base R
dvreq1.o ⊢ U = Unit ⁡ R
dvreq1.d ⊢ × ˙ = / r ⁡ R
dvreq1.t ⊢ 1 ˙ = 1 R
Assertion dvreq1 ⊢ R ∈ Ring ∧ X ∈ B ∧ Y ∈ U → X × ˙ Y = 1 ˙ ↔ X = Y

Proof

Step Hyp Ref Expression
1 dvreq1.b ⊢ B = Base R
2 dvreq1.o ⊢ U = Unit ⁡ R
3 dvreq1.d ⊢ × ˙ = / r ⁡ R
4 dvreq1.t ⊢ 1 ˙ = 1 R
5 oveq1 ⊢ X × ˙ Y = 1 ˙ → X × ˙ Y ⋅ R Y = 1 ˙ ⋅ R Y
6 eqid ⊢ ⋅ R = ⋅ R
7 1 2 3 6 dvrcan1 ⊢ R ∈ Ring ∧ X ∈ B ∧ Y ∈ U → X × ˙ Y ⋅ R Y = X
8 1 2 unitcl ⊢ Y ∈ U → Y ∈ B
9 1 6 4 ringlidm ⊢ R ∈ Ring ∧ Y ∈ B → 1 ˙ ⋅ R Y = Y
10 8 9 sylan2 ⊢ R ∈ Ring ∧ Y ∈ U → 1 ˙ ⋅ R Y = Y
11 10 3adant2 ⊢ R ∈ Ring ∧ X ∈ B ∧ Y ∈ U → 1 ˙ ⋅ R Y = Y
12 7 11 eqeq12d ⊢ R ∈ Ring ∧ X ∈ B ∧ Y ∈ U → X × ˙ Y ⋅ R Y = 1 ˙ ⋅ R Y ↔ X = Y
13 5 12 imbitrid ⊢ R ∈ Ring ∧ X ∈ B ∧ Y ∈ U → X × ˙ Y = 1 ˙ → X = Y
14 2 3 4 dvrid ⊢ R ∈ Ring ∧ Y ∈ U → Y × ˙ Y = 1 ˙
15 14 3adant2 ⊢ R ∈ Ring ∧ X ∈ B ∧ Y ∈ U → Y × ˙ Y = 1 ˙
16 oveq1 ⊢ X = Y → X × ˙ Y = Y × ˙ Y
17 16 eqeq1d ⊢ X = Y → X × ˙ Y = 1 ˙ ↔ Y × ˙ Y = 1 ˙
18 15 17 syl5ibrcom ⊢ R ∈ Ring ∧ X ∈ B ∧ Y ∈ U → X = Y → X × ˙ Y = 1 ˙
19 13 18 impbid ⊢ R ∈ Ring ∧ X ∈ B ∧ Y ∈ U → X × ˙ Y = 1 ˙ ↔ X = Y