Metamath Proof Explorer


Theorem efald2

Description: A proof by contradiction. (Contributed by Giovanni Mascellani, 15-Sep-2017)

Ref Expression
Hypothesis efald2.1 ⊢ ¬ φ → ⊥
Assertion efald2 ⊢ φ

Proof

Step Hyp Ref Expression
1 efald2.1 ⊢ ¬ φ → ⊥
2 1 adantl ⊢ ⊤ ∧ ¬ φ → ⊥
3 2 efald ⊢ ⊤ → φ
4 3 mptru ⊢ φ