Metamath Proof Explorer


Theorem elcnvcnvlem

Description: Two ways to say a set is a member of the converse of the converse of a class. (Contributed by RP, 20-Aug-2020)

Ref Expression
Assertion elcnvcnvlem ⊢ A ∈ B -1 -1 ↔ A ∈ V × V ∧ I ⁡ A ∈ B

Proof

Step Hyp Ref Expression
1 cnvcnv ⊢ B -1 -1 = B ∩ V × V
2 incom ⊢ B ∩ V × V = V × V ∩ B
3 1 2 eqtri ⊢ B -1 -1 = V × V ∩ B
4 3 eleq2i ⊢ A ∈ B -1 -1 ↔ A ∈ V × V ∩ B
5 elinlem ⊢ A ∈ V × V ∩ B ↔ A ∈ V × V ∧ I ⁡ A ∈ B
6 4 5 bitri ⊢ A ∈ B -1 -1 ↔ A ∈ V × V ∧ I ⁡ A ∈ B