Metamath Proof Explorer


Theorem ensucne0OLD

Description: A class equinumerous to a successor is never empty. (Contributed by RP, 11-Nov-2023) (Proof modification is discouraged.) (New usage is discouraged.)

Ref Expression
Assertion ensucne0OLD ⊢ A ≈ suc ⁡ B → A ≠ ∅

Proof

Step Hyp Ref Expression
1 encv ⊢ A ≈ suc ⁡ B → A ∈ V ∧ suc ⁡ B ∈ V
2 1 simprd ⊢ A ≈ suc ⁡ B → suc ⁡ B ∈ V
3 en0 ⊢ A ≈ ∅ ↔ A = ∅
4 3 biimpri ⊢ A = ∅ → A ≈ ∅
5 4 a1i ⊢ suc ⁡ B ∈ V → A = ∅ → A ≈ ∅
6 nsuceq0 ⊢ suc ⁡ B ≠ ∅
7 0sdomg ⊢ suc ⁡ B ∈ V → ∅ ≺ suc ⁡ B ↔ suc ⁡ B ≠ ∅
8 6 7 mpbiri ⊢ suc ⁡ B ∈ V → ∅ ≺ suc ⁡ B
9 5 8 jctird ⊢ suc ⁡ B ∈ V → A = ∅ → A ≈ ∅ ∧ ∅ ≺ suc ⁡ B
10 ensdomtr ⊢ A ≈ ∅ ∧ ∅ ≺ suc ⁡ B → A ≺ suc ⁡ B
11 sdomnen ⊢ A ≺ suc ⁡ B → ¬ A ≈ suc ⁡ B
12 10 11 syl ⊢ A ≈ ∅ ∧ ∅ ≺ suc ⁡ B → ¬ A ≈ suc ⁡ B
13 9 12 syl6 ⊢ suc ⁡ B ∈ V → A = ∅ → ¬ A ≈ suc ⁡ B
14 13 necon2ad ⊢ suc ⁡ B ∈ V → A ≈ suc ⁡ B → A ≠ ∅
15 2 14 mpcom ⊢ A ≈ suc ⁡ B → A ≠ ∅