Metamath Proof Explorer


Theorem esumeq1d

Description: Equality theorem for an extended sum. (Contributed by Thierry Arnoux, 19-Oct-2017)

Ref Expression
Hypotheses esumeq1d.0 ⊢ Ⅎ k φ
esumeq1d.1 ⊢ φ → A = B
Assertion esumeq1d ⊢ φ → ∑ * k ∈ A C = ∑ * k ∈ B C

Proof

Step Hyp Ref Expression
1 esumeq1d.0 ⊢ Ⅎ k φ
2 esumeq1d.1 ⊢ φ → A = B
3 eqidd ⊢ φ ∧ k ∈ A → C = C
4 1 2 3 esumeq12dvaf ⊢ φ → ∑ * k ∈ A C = ∑ * k ∈ B C